Assume that nickels are measured in diameter, and we want to form the certain number of nickels to form an inch. Let the diameter of the nickel be 22 millimeters, which is 2.2 centimeters. Note that 1 inch = 2.54 centimeters. Then, there is no definite number of nickels that exactly form an inch since: 2.54 centimeters * 1 nickel / 2.2 centimeters = 1.15... nickels [and we obtain the "incomplete" nickel to form an inch]!
A single nickel in the United States has a diameter of 0.835 inches. Therefore, it would take approximately 1.2 nickels to make one inch.
US nickels are 1.95 mm thick. A US inch is 25.4 mm so you would need 25.4 / 1.95 = 13 coins.
A nickel has a thickness of approximately 1.95 millimeters. Since there are 25.4 millimeters in an inch, you would need about 13 nickels stacked to reach an inch (25.4 mm ÷ 1.95 mm ≈ 13).
it's a trick question. A 100-inch tall stack of nickels is ... 100 inches tall.
Nickels are 1.95 mm thick, although that could vary depending on wear. 1.95mm is about 0.076-0.077 inches. So, it would be about 1298-1316 nickels.
There are 13 stacked nickels in an inch, 12 inches in a foot and the Empire State building is 1250 feet high to the 102nd floor so 195,000 nickels would be needed.
There are 40 nickels in a roll of nickels.
340 nickels
700 nickels
235 nickels.
390 nickels.