The median of 88, 92, 96, 99, and 100 is 96 because median pretty much means middle and the middle number is 96.
88/92 * 100 = 96% ====
It is 89
The median is 87.
80, 84, 88, 92, 96, 100
To find the median of a set of numbers, you first need to arrange them in numerical order. Once you have them in order, the median is the middle number. If there is an odd number of values, the median is the middle number. If there is an even number of values, the median is the average of the two middle numbers. In this case, the numbers arranged in numerical order are: 78, 81, 82, 88, 88, 88, 89, 91, 91, 92, 93, 94, 95, 96, 98. Since there are 15 numbers, the median will be the 8th number, which is 89.
It is: (96+100+92)/3 = 96
To find the interquartile range (IQR) of the data set 88, 92, 80, 80, 82, 93, 96, 95, first, we need to arrange the numbers in ascending order: 80, 80, 82, 88, 92, 93, 95, 96. Next, we determine the first quartile (Q1) and the third quartile (Q3); Q1 is the median of the first half (80, 80, 82, 88), which is 81, and Q3 is the median of the second half (92, 93, 95, 96), which is 94. The IQR is then calculated as Q3 - Q1, resulting in an IQR of 94 - 81 = 13.
-88
92
It is 82
To calculate the average of the numbers 86, 92, 88, and 96, add them together: 86 + 92 + 88 + 96 = 362. Then, divide the sum by the number of values, which is 4: 362 ÷ 4 = 90.5. Therefore, the average is 90.5.
88 because you're taking 4 away each time.