As far as currency is concerned, the word "Pound" did not even exist until about 1100 AD.
D/4 = 1.7 Multiply both sides by 4 to find the value of D:- D = 6.8
um.........b or d
D = b²-4ac a=2, b=5, c=4 D=5²-4(2*4) D=25-4(8) D=25-32 D=-7■
It is 138.
To determine if the line passing through (-2, 4) and (5, d) is parallel to the graph of y = 3x + 4, we need to compare the slopes. The slope of the given line y = 3x + 4 is 3. The slope of the line passing through (-2, 4) and (5, d) can be calculated using the formula (y2 - y1) / (x2 - x1). So, (d - 4) / (5 - (-2)) = 3. Solving this equation will give you the value of d.
It would depend on the density of the fluid. N * 0.453592 / D N is the value of pounds per minute. 0.453592 is the number of pounds in a kilogram. D is the fluid density in kilograms per liter. For water, this would be 1.
4
The value of a coin marked "Georgius III D G Britanniarum Rex F D 1819" varies based on its condition, rarity, and market demand. This coin is a British silver crown featuring King George III, and its value can range from a few pounds to several hundred pounds for coins in excellent condition. For a precise valuation, it's best to consult a numismatic expert or a reputable coin dealer.
The gravitational force between two masses is given by the equation: F = G * (m1 * m2) / d^2 where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and d is the distance between the two objects. If the distance between the two masses is quadrupled, the distance between the two objects (d) in the equation will be 4 times greater, so the denominator of the equation will be 4^2 = 16 times greater. To see the effect of this change on the gravitational force, we'll divide the new value by the original value: (1/(4^2)) = 1/16 So, when the distance between two masses is quadrupled, the gravitational force between them is 1/16 of its original value.
i have the paint etween two fireshow can i sell it
Two - D & G are both worth 2pts a piece.
its about 123 pounds ;D