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The square roots are -13i and 13i where i is the imaginary square root of -1.
The expression (13i) represents a complex number where (i) is the imaginary unit, defined as the square root of (-1). In this case, (13i) indicates that the number has no real part and a purely imaginary part of 13. Complex numbers like (13i) are often used in mathematics and engineering to represent quantities that have both magnitude and direction, particularly in fields such as electrical engineering and signal processing.
√ -169 = 13i
(-169).5 = 13i
Yes, (13i) is a pure imaginary number. A pure imaginary number is one that can be expressed in the form (bi), where (b) is a real number and (i) is the imaginary unit. Since (13i) has no real part and consists solely of the imaginary part (13), it qualifies as pure imaginary.
first sum i=13i+3i=16i,then sum j=0.5j+(-17j)=0.5j-17j=-16.5j,therfor the answer is 16i-16.5j
It will be in 3rd Quadrant because cosine and sine both are negative in 3rd Quadrant
canto 13I think it's actually Canto XII.
You can probably just start by sharing your favorite Scripture. Mine is: Philippians 4:13I can do everything through him who gives me strength.
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emoetry is like when emos use dead stuff and violence and put it in a song or poembyAshley travers6th grademiss.millsim 13i love tony!