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To determine the kVA needed to run six 2-ton air conditioners, first, calculate the total load. Each 2-ton AC unit typically consumes around 2.5 kW, so six units would require approximately 15 kW (2.5 kW x 6). To convert kW to kVA, divide by the power factor (usually around 0.8 for AC units), resulting in about 18.75 kVA (15 kW / 0.8). Therefore, you would need at least 19 kVA to safely run six 2-ton air conditioners.

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2mo ago

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To determine how many hours a 12,000 BTU air conditioner can run on a KVA inverter system, you first need to convert BTUs to watts. A 12,000 BTU unit typically consumes around 1,200 watts. If your inverter system is, for example, 1 KVA (1,000 watts), it would not be able to power the air conditioner continuously, as the AC requires more power than the inverter can supply. Therefore, the air conditioner would run for a limited time, depending on the battery capacity of the inverter system and its efficiency.


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It should do so easily; 1.5 HP is only about 1100 watts, which is significantly less than 3.5 kVA.


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To convert amps to kilovolt-amperes (kVA), you need to know the voltage level. The formula is kVA = (Amps × Volts) / 1000. For example, at 240 volts, 800 amps would equal 192 kVA, while at 480 volts, it would equal 384 kVA. Thus, the kVA value will vary depending on the voltage used in the calculation.


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To convert 2 kW to kVA in single phase, you need to know the power factor. If we assume a power factor of 0.8 (common for many single-phase loads), the conversion formula is kVA = kW / power factor. Therefore, for 2 kW at a power factor of 0.8, the result would be 2 kVA / 0.8 = 2.5 kVA.


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