A signal starts at point X. As it travels to point Y, it loses 10db. At point Y, the signal
is boosted by 5db. As the signal travels to point Z, it loses 7db. What is the db
strength of the signal at point Z?
What is the decibel loss of a signal that starts at point A with a strength of 2000 watts and ends at point B with a strength of 400 watts?That is impossiple. If you have a light bulb of 100 watts. This power stays fixed in the lamp and does not decrease with distance!If you mean a sound source, only the sound pressure in pascals or the sound pressure level in dB is decreasing with distance from the source. Or the sound intensity in watts per square meter or the sound intensity level in watts is decreasing with distance.Scroll down to related links and look at "Sound intensity I and the inverse square law 1/r2"This question is talking about the fundamentals between data and signals in data communication. It has nothing to do with a light bulb and is not impossible. Here is how it is done. The decibel is a relative measure of signal loss or gain and is expressed as dB = 10 × log10 (P2 / P1) in which P2 and P1 are the ending and beginning power levels of the signal expressed in watts.So in this case where a signal starts with a strength of 2000 watts and ends with a strength of 400 watts the calculation would be:dB = 10 × log10 (400 /2000)dB = 10 × log10 (.2)dB = 10 × (-.69)dB = -6.9dB
In MSWord : F7
microprocessor microprocessor
Yes it is.
I think there's one called Q2.
Escapadee'
What is the decibel loss of a signal that starts at point A with a strength of 2000 watts and ends at point B with a strength of 400 watts?That is impossiple. If you have a light bulb of 100 watts. This power stays fixed in the lamp and does not decrease with distance!If you mean a sound source, only the sound pressure in pascals or the sound pressure level in dB is decreasing with distance from the source. Or the sound intensity in watts per square meter or the sound intensity level in watts is decreasing with distance.Scroll down to related links and look at "Sound intensity I and the inverse square law 1/r2"This question is talking about the fundamentals between data and signals in data communication. It has nothing to do with a light bulb and is not impossible. Here is how it is done. The decibel is a relative measure of signal loss or gain and is expressed as dB = 10 × log10 (P2 / P1) in which P2 and P1 are the ending and beginning power levels of the signal expressed in watts.So in this case where a signal starts with a strength of 2000 watts and ends with a strength of 400 watts the calculation would be:dB = 10 × log10 (400 /2000)dB = 10 × log10 (.2)dB = 10 × (-.69)dB = -6.9dB
Typically, the electrical signal that travels from the dendrites across the cell body travels by cable conduction properties (like cable TV). Once the signal reaches the axon hillock, which is the spot where the axon branches off the cell body, the electrical signal starts traveling by action potentials (and maybe some cable conduction). The signal travels to the terminal end of the axon where it initiates a calcium influx, which in turn initiates a release of neurotransmitter to act on the next, post-synaptic neuron. The axon is the long process (arm) that extends from the first cell body to the next neuron.
Lightning typically starts from the clouds and travels towards the ground.
PakistanIt starts in Tibet, travels through India and ends in Sindh Pakistan.
May be a bad flasher
Then it raises the following question: what IS the question?
Sunlight
Ss
the turn signal switch in the steering column
conditioning- A.K.A. strength work outs
Tensile strength Tangent Thesis Temperature Toluene