15.242.55.6227 is an invalid IP address.
Subnet Mask provides Network & Class Identificationfor an IP Address.
No, end devices cannot have .0 address assigned to them. It loosely refers to the entire network subnet.
depends on the subnet mask ie/ 255.255.255.252 which would mean 175.124.35.0,4,8,12,16etc etc are networks and 175.124.35.1 & .2 are hosts. .3 is the broadcast address for that subnet.
It will send the frame to all hosts except host A.This is a MAC broadcast address. All hosts on that subnet will receive the packet or frame. With the exception of the sending host of course.
Assuming the subnet mask is 255.255.255.0 then... You range of total addresses is from 192.168.1.0 - 192.168.1.255 However, the first and last IP addresses cannot be assigned to hosts since they are reserved for internal usage. The first address, 192.168.1.0, is the subnet address. The last address, 192.168.1.255, is the broadcast address. Thus, the host range is from 192.168.1.1 - 192.168.1.254
The IP address 172.30.0.0 is a private IP address in the Class B range, which has a default subnet mask of 255.255.0.0 (or /16). If you use the default mask, you can create 65,536 addresses (2^16), allowing for 65,534 usable hosts per subnet (subtracting 2 for the network and broadcast addresses). If you further subnet this address, the number of subnets and hosts per subnet will depend on the subnet mask you choose. For example, using a /24 subnet mask would give you 256 subnets with 254 usable hosts in each.
A subnet mask for a /512 subnet is not valid because subnet masks are defined in powers of two, and the maximum number of hosts in a subnet is limited by the number of bits in the IP address (32 bits for IPv4). The largest valid subnet mask is /32, which allows for a single IP address. However, if you meant a subnet that allows for 512 hosts, the correct subnet mask would be /23, which provides 512 addresses (510 usable for hosts).
4.1 to 7.254
To implement subnetting, first determine the network's requirements, including the number of subnets and hosts per subnet. Next, choose a suitable subnet mask that allows for the desired number of subnets and hosts by calculating the available bits in the IP address. Divide the IP address space into subnets based on the selected mask, ensuring that each subnet has a unique network address. Finally, configure the devices on the network to recognize the new subnets by updating their IP addresses and subnet masks accordingly.
In a Class A address, the default subnet mask is 255.0.0.0, allowing for a large number of hosts within a single network, but with 16 bits designated for the subnet ID, the subnet mask becomes 255.255.0.0. In contrast, a Class B address has a default subnet mask of 255.255.0.0, and with 8 bits for the subnet ID, the subnet mask would typically be 255.255.255.0. Thus, the key difference lies in the number of bits allocated for the subnet ID and the resulting subnet masks, affecting the number of available subnets and hosts per subnet.
To create a subnet ID, you start with the network's base IP address and subnet mask. The subnet mask determines how many bits are allocated for the network and how many for the hosts. By applying the subnet mask to the base IP address, you can identify the subnet ID, which represents the network portion of the address. For example, if your base IP is 192.168.1.0 with a subnet mask of 255.255.255.0, the subnet ID is 192.168.1.0.
Network address 10.1.1.0 Subnet mask 255.255.255.192255 - 62 = 193Because the value 255 is the broadcast address we get the number 192193 - 1 = 192the answer is 192Sorry for my poor English i mean my bad English.
172.16.4.255
172.16.4.225
In MikroTik RouterOS, Layer-3 communication between two hosts can be achieved using an address subnet of at least a /30 (255.255.255.252) for point-to-point links or larger subnets like /24 (255.255.255.0) for networks with multiple hosts. Each host must have a unique IP address within the same subnet, and they must be correctly configured with the appropriate gateway settings. Proper routing must also be established to facilitate communication between the hosts.
The subnet mask is used for this purpose. It indicates how much of the address is for network, and the remaining part is for the hosts.
To determine the usable hosts for the IP address 176.34.56.91, we need to know its subnet mask. Assuming a common subnet mask of 255.255.255.0 (or /24), the usable host range would be from 176.34.56.1 to 176.34.56.254, meaning there are 254 usable IP addresses in this subnet. The first address (176.34.56.0) is the network address, and the last address (176.34.56.255) is the broadcast address.