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There are 32...

00000000

00000001

00000010

00000011

00000100

00000101

00000110

00000111

00001000

00001001

00001010

00001011

00001100

00001101

00001110

00001111

00010000

00010001

00010010

00010011

00010100

00010101

00010110

00010111

00011000

00011001

00011010

00011011

00011100

00011101

00011110

00011111

The most significant three bits in an octet (a byte) are required to be 0 (zero). No further requirement is made about the state of the remaining 5 bits; the bit pattern in the byte thus is 000x xxxx (where 'x' can be either '0' or '1').

Five bits of 'x' allow for 25 = 32 combinations.

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Related Questions

How many bit strings of length 10 both begin and end with a1?

To find the number of bit strings of length 10 that begin and end with "1", we fix the first and last bits as "1". This leaves us with 8 bits in the middle, which can each be either "0" or "1". Therefore, there are (2^8 = 256) different combinations for the 8 middle bits. Thus, there are 256 bit strings of length 10 that begin and end with "1".


How many bit strings of length ten both begin and end with 1?

its 2 raised to power 8 i.e 256


In a bit string length 12 How many begin with 110?

You are essentially asking how many different bit strings of length 9 are there, as the first 3 bits are fixed. The answer is 2^9 = 512.


How many bit strings of length 8 are there which begin with a 0 and end with a 0?

-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.


How many strings of three decimal digits begin with an odd digit?

There are 500 of 3-digit numbers begin with an odd one (100-199, 300-301, 500-599,700-799, and 900-999). In terms of "how many strings of", may filter or expand the above answer.


How many different eight-bit strings begin with 100?

Three of the bits are already determined. That leaves 5 .25 = 32


How many bit strings are there of length eight?

Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.


How many bit strings of length 10 have?

1024


How many bit strings of length 8 contain exactly three 1's?

56 The number of triples of 1s on 8 bits


How many bit strings of length 5 are there?

There are (2^5) bit strings of length 5, as each bit can be either 0 or 1. Therefore, the total number of bit strings is (32).


How many bit strings of length 3 have exactly two 1s?

Three of them ... the binary numbers 3, 5, and 6. 011 101 110


How many bit strings are there of length ten?

210=1024

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