The formula is 9*9*9*9*
* * * * *
The above answer is wrong on two counts: First, there are ten digits to chose from, not nine. Second, the answer is in terms of permutations ie 1234 being different from 2341. However, both these are the same combination.
The correct answer is 10*9*8*7/(4*3*2*1) = 210.
The number of distinct combinations that can be created with n bits is 2n.
Robots are run by computers which communicate with numbers, represented by binary combinations of high and low voltages of electricity.
The answer in case your wondering is yes, I have done it a few different times. There are as many ways to find a person for free as there are numbers and combinations of numbers. There are basic methods and there are more advanced methods of doing it. The internet is one way, another way is by phone, and another is by personal investigating and asking questions of people.
You add All the numbers together and the divide by how many numbers there is.
XS-3 (Excess-3) code conversion is primarily used in digital systems to encode decimal numbers in a way that simplifies arithmetic operations and error detection. Each decimal digit is represented by its corresponding binary value plus three, which helps in avoiding ambiguity during addition and subtraction. This encoding is particularly useful in applications involving digital display systems, such as calculators and digital clocks, where it ensures that invalid combinations do not occur. Additionally, XS-3 can facilitate easier implementation of decimal arithmetic in hardware.
9
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
8C3 = 56 of them
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
I dont understand what you are asking.
There are: 10C3 = 120
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
13 combinations of 3
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.