Breadth-First Search (BFS) explores all neighbors of a node before moving on to the next level, while Dijkstra's algorithm prioritizes nodes based on their distance from the start node. This means BFS may not always find the shortest path, especially in weighted graphs, whereas Dijkstra's algorithm guarantees the shortest path. Dijkstra's algorithm is more efficient in finding the shortest path in weighted graphs due to its priority queue implementation, while BFS is more efficient in unweighted graphs.
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Yes they will yield the same result. But this is iif they have the same topology . That is if the topology remains the same 100% chances to yield the same result But if the topology differs. That is both have diff topology they will not yield the same result in most of the cases. This is a good debatable question. If you see the differences in the algorithms , one is distance vector and one is link state. all i can say is if the n/w large , then bellman ford will not converge soon. So for large n/ws Dijkstras is preferred. But for smaller n/ws Bellman is preferred because its based on Distance/hops. So in short they will yield same results if the topology is the same, But if the topology differs it can be found out by checking the algorithms flow chart. And if there is any negetive weights Bellman will converge soner than Dijkstras. I hope this should answer your question. Good question btw but no defined answer for this one. Hpe this was Helpful.