The analytical equation for determining the trajectory of a projectile is the projectile motion equation, which is given by:
y xtan - (gx2) / (2v2cos2)
where:
The result of 2 mod 3 in the given equation is 2.
To reduce the expression of a mathematical equation using Mathematica, you can use the Simplify function. Simply input the equation into Mathematica and apply the Simplify function to simplify and reduce the expression.
wait is that algerbra? then what equaiton
When the equation 2 raised to the power of log n is simplified, it equals n.
The square root of n in the equation x n is the value that, when multiplied by itself, equals n.
Its an equation used to find the 2D motion of a projectile; y=xtan*0-gx2/2u2cos2* where * represents an angle b/w them
Yes, a ball thrown in an arbitrary direction follows the equation of projectile motion as long as the only force acting on it is gravity. The motion can be broken down into horizontal and vertical components, with the horizontal motion being constant and the vertical motion following a parabolic trajectory.
you find the hard equation and simplify it....
introduction of lagrange equation
The quadratic equation has many application related to resolving and modelling daily life problems. two examples are in archery and rifle sports. The trajectory of the projectile can follow a ballistic arc. The arc itself can be explained and graphically illustrated by the quadratic equation.
How is this different from determining if a value is a solution to an equation?
determine the equation for trajectory with ahead of 7.0m and velocity cofficient of .95
You go and look up the equation and it should be there
Assuming no air resistance, the time it takes for the projectile to return to its starting point is twice the time it takes to reach the highest point of its trajectory. The time to reach the highest point can be calculated using the equation: time = initial velocity / acceleration due to gravity. Therefore, the total time for the projectile to return would be around 6 seconds.
square root of 2(d)/r squared
Not necessarily. The equation of a projectile, moving under constant acceleration (due to gravity) is a parabola - a non-linear equation.
The answer will depend on what quantity is being measured by c.