A classful class B network has a network range of 128 - 191. For host addresses, anything that is legal for an IP address in the last 2 octets would be a valid host address for a class B with no subnets.
256
65,534
If you aren't subnetting, then the host range for this network would be: 190.254.0.0 - 190.254.255.255 The above shows the IP address range, but not all addresses would be usable (mostly the first and the last addresses would probably be not assignable to a device).
190.254.1.29
"The RFC 1918 private network numbers are 10.0.0.0, Class Bs between 172.16.0.0 and 172.31.0.0 inclusive, and all Class C networks that begin with 192.168. All addresses that begin with 127 are reserved, but not as valid private IP addresses."
No, because the range for class C addresses is 192 - 223, and the first octet of the address 191.76.43.10 is a class B address.
No, 255.255.0.255 is not a valid Class A address. In fact, it is a broadcast address used in Class B networks. Class A addresses range from 1.0.0.0 to 126.255.255.255, and the highest address in this range is 126.255.255.255. Additionally, the address 255.255.255.255 is reserved for the limited broadcast address, not for any specific class.
There are 2^24 host in class A but (2^24)-2 hosts are valid since the first and last address are reserved .
It is unlikely that you will find the IP address 192.168.250.10 on the internet because the .10 represents the number of host connected to an individual network. Also, IEEE recommends that the following IP addresses be used for private networks: 10.0.0.0 through 10.255.255.255 Class A 172.16.0.0 through 172.31.255.255 Class B 192.168.0.0 through 192.168.255.255 Class C
You can use up to 254 devices in this case.
An example of a valid class C address would be 192.168.6.200
In order to dispose of a session that is no longer needed, you can call the invalidate() method of the HttpServlet class. Assuming you have an instance of HttpServlet called 'session' you would do this: session.invalidate();