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A problem is 'in NP' if there exists a polynomial time complexity algorithm which runs on a Non-Deterministic Turing Machine that solves it.
A problem is 'NP Hard' if all problems in NP can be reduced to it in polynomial time, or equivalently if there is a polynomial-time reduction of any other NP Hard problem to it.
A problem is NP Complete if it is both in NP and NP hard.
What else can I help you with?
Difference between np hard and np complete?
All NP complete problems are NP hard problems when solved in a different way. But, all NP hard problems are not NP complete. Ex: 1. Traveling salesman problem. It is both NP hard and NP complete. We can find that whether the solution is correct or not in the given period of time. In this way, it is NP complete. But, to find the shortest path, i.e. optimization of Traveling Salesman problem is NP hard. If there will be changing costs, then every time when the salesperson returns to the source node, then he will be having different shortest path. In this way, it is hard to solve. It cannot be solved in the polynomial time. In this way, it is NP hard problem. 2. Halting problem. 3. Sum of subset problem.
Is prime factorization an NP-complete problem?
Yes, prime factorization is not an NP-complete problem. It is in fact in the complexity class NP, but it is not known to be NP-complete.
Is the clique problem NP-complete?
Yes, the clique problem is NP-complete.
Is the partition problem NP-complete?
Yes, the partition problem is NP-complete.
Is Node-disjoint paths np-complete?
No. Verifying if I'm lying is NP-Complete.
Is finding a dense subgraph NP-complete?
Yes, finding a dense subgraph is NP-complete.
Is interval scheduling an NP-complete problem?
Yes, interval scheduling is an NP-complete problem.
Is the path selection problem NP-complete?
Yes, the path selection problem is NP-complete.
Can you prove that the problem is NP-complete?
Proving that a problem is NP-complete involves demonstrating that it is both in the NP complexity class and that it is at least as hard as any other problem in NP. This typically involves reducing a known NP-complete problem to the problem in question, showing that a solution to the problem in question can be used to solve the known NP-complete problem efficiently.
Is the problem of subgraph isomorphism being NP-complete?
Yes, the problem of subgraph isomorphism is NP-complete.
What is set difference between recursive and recursively enumerable but not recursive?
All recursive Languages are recursively enumerable. But not all the recursively enumerable languages are recursive. It is just like NP complete.
What is the proof that the Clique Problem is NP-complete?
The proof that the Clique Problem is NP-complete involves showing that it is both in the NP complexity class and that it is as hard as any problem in NP. This is typically done by reducing a known NP-complete problem, such as the SAT problem, to the Clique Problem in polynomial time. This reduction demonstrates that if a polynomial-time algorithm exists for the Clique Problem, then one also exists for the known NP-complete problem, which implies that the Clique Problem is NP-complete.
