Do you have to hit a key to space? Yes, they are keystrokes.
To calculate the number of words in 85 keystrokes per minute, it's commonly estimated that one word is equivalent to about 5 keystrokes (including spaces and punctuation). Therefore, at 85 keystrokes per minute, you would be typing approximately 17 words per minute (85 ÷ 5 = 17).
To convert keystrokes to words per minute (WPM), a common estimate is that one word equals five keystrokes (including spaces and punctuation). Therefore, 5,500 keystrokes would be approximately 1,100 words (5,500 divided by 5). If this is measured over a minute, it would equate to 1,100 words per minute.
Spaces are not words. Nor do you type spaces into words. Spaces separate words.
To convert net keystrokes into words per minute (WPM), you typically divide the total keystrokes by an average word length, often estimated at 5 characters per word, including spaces and punctuation. For 140 net keystrokes, this results in 140 ÷ 5 = 28 words. If this typing took one minute, that would equal 28 WPM.
To convert keystrokes to words, a common estimate is that one word equals about 5 keystrokes (including spaces and punctuation). Therefore, 3000 keystrokes would be approximately 600 words (3000 divided by 5). If this is typed over the course of one minute, it would equate to a typing speed of around 600 words per minute. However, typing speeds can vary significantly based on the individual and context.
You have to count how many spaces that your rock went when you threw it and if you want to make it more educational then you can count how many spaces you hopped on
Accuracy % = ((keystrokes - errors) / keystrokes) * 100 Example: 500 keystrokes - 25 errors = 475 accurate keystrokes 95% = ((500 - 25) / 500) * 100 = (475 / 500) * 100) = .95 * 100 Check: 500 keystrokes - 25 errors = 475 accurate keystrokes 500 keystrokes * 95% accuracy = 500 * .95 = 475 accurate keystrokes 475=475=true! --------------------------- Original Poster's Method: --------------------------- number of mistakes divided by the number of keystrokes multiply by 100 subtract from 100
LEN will count spaces in a cell as well as other characters. So there is no special way needed to count spaces as they will be included. If you are counting what is in cell A3 for example, then you would use the function: =LEN(A3) To count only the spaces in a cell and ignoring other characters, then you could try this approach: =LEN(A3)-LEN(SUBSTITUTE(A3," ","")) It gets the full length and then substracts the length of the text with the spaces removed.
Yes
For only the digits: 5,888,896. More if there are commas as thousands separators (as in this answer), or spaces between numbers (999,999 of those).
Yes, they do
There are nine numbers which contain only one digit. There are 90 numbers which contain two digits. There are 900 numbers which contain three digits. There is one number which contains four digits.Therefore, the number of digits is equal to (9x1)+(90x2)+(900x3)+4 = 2893 digits. If this includes spaces, there would be 999 spaces, therefore there would be 3892 keystrokes.