Given a page size of 2M and 1G of virtual memory, the minimum size of an entry in the process page table is 11 bits, excluding status flags, and there will be 2,048 (64K) entries in the process page table, but see the discussion below for other, probably more useful answers.
The answer depends on the size of physical memory, and on whether or not the page table requires a full base address or not. First of all, a page size of 2mb is not standard - a typical page is 1K to 4K, 4K being using in the Intel processors, but this answer assumes a 2mb page size.
Lets assume the base address in the page table does not require a full base address - a usual configuration. That means the base address is 11 bits. (232 = 1,073,741,824 = 1G. 221 = 2,097,152 = 2M. 32 - 21 = 11) That means the base table field is 11 bits (211 = 2048. However, page table entries are usually rounded up to the nearest byte, 16 bits, so 216 = 65,536 = 64K. This also give room for status and access control bits.
However, the question did not specify the size of physical memory, so the above answer assumed the virtual memory was the same as physical memory, not a usual configuration.
Lets assume a 64GB physical memory size, since you seem to be talking about very large processors. 236 = 68,719,476,736 = 64T. 215 = 32,767 = 32K. 36 - 21 = 15. 15 bits per entry, rounded up to the nearest byte, is still 64K bytes, so we are still talking about 64K.
Although your question did not include status bits, and 1 bit is not enough for a reasonable implementation, and most architectures also use a factor of 2 for their hardware page table, in order to minimize complexity, so we are talking about 128K.
Last, you asked "minimum size". Most processor include a length attribute to the page table, so 64K (128K) is the maximum, and it could be smaller, depending on actual virtual pool size.
Just put the data in order and look at the biggest and smallest data entries.
In the minimum accounting entries, at least two accounts are involved due to the double-entry accounting system. This system requires that every transaction affects at least one debit and one credit, ensuring that the accounting equation (Assets = Liabilities + Equity) remains balanced. Thus, the minimum is two accounts, but more can be involved depending on the complexity of the transaction.
It can be as long ad it has to be, but it must have a minimum of two entries, one debit and one credit and it much all balance.
There is always two entries at minimum. Remember the accounting equation... Assets = Liabilities + Owners Equity (Stockholders Equity) For every action that must be an equal and opposite reaction. Simply put for every Debit there must be an equal Credit. So there has to be at least two entries, one debit and one credit.
The bordered hessian matrix is used for fulfilling the second-order conditions for a maximum/minimum of a function of real variables subject to a constraint. The first row and first column of the bordered hessian correspond to the derivatives of the constraint whereas the other entries correspond to the second and cross partial derivatives of the real-valued function. Other than the bordered entries, the main diagonal of the sub matrix consists of entries for the second partial derivatives. All other entries of the sub matrix off of the main diagonal correspond to all combinations of cross partials. Evaluating the determinant of the bordered hessian will allow one to determine if the function attains its maximum or minimum at the stationary points, which by the way are limited in the fact that they must both satisfy the gradient equations and the constraint.
Bare minimum. Ex. "That is the bare minimum for getting into the program."
The opposite of the word minimum is maximum.
Yes. (But not the other way round - a local minimum is not necessarily an absolute minimum.)Yes. (But not the other way round - a local minimum is not necessarily an absolute minimum.)Yes. (But not the other way round - a local minimum is not necessarily an absolute minimum.)Yes. (But not the other way round - a local minimum is not necessarily an absolute minimum.)
30% off of minimum wages = 30% discount applied to the minimum wages = minimum wages - (30% * minimum wages)
Minimum
The minimum wage is $7.25, the same as federal minimum wage.
Friday will be a minimum day for the students. The minimum payment was $50.00