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How many bits are borrowed from a class B host address to create 30 new subnets?
5 bits are necessary to create up to 30 subnets.
What does it mean to borrow 4 bits for subnets?
When you borrow bits for a subnet you are intruding into the client portion of an IP address. As a result, you will lose clients in your network because the "borrowed" portion becomes the extended network prefix. This allows you to separate your bigger network into smaller, logical networks (subnets). The number of bits borrowed will indicate the total number of smaller subnets that you can support in your network. In each case, regardless of class of address, borrowing 4 bits gives a total of 14 subnets (in the classical sense) and 16 subnets (in Cisco).
Assume all devices are using default configurations How many subnets are required to address the topology that is shown?
3
How many host bits are borrowed if four subnets are created?
3
What gateway interprets its outbound request to other subnets and then interprets its inbound requests from other subnets is called?
Default Gateways
How many subnets and hosts per subnts can you get from 172.30.0.0?
The IP address 172.30.0.0 is a private IP address in the Class B range, which has a default subnet mask of 255.255.0.0 (or /16). If you use the default mask, you can create 65,536 addresses (2^16), allowing for 65,534 usable hosts per subnet (subtracting 2 for the network and broadcast addresses). If you further subnet this address, the number of subnets and hosts per subnet will depend on the subnet mask you choose. For example, using a /24 subnet mask would give you 256 subnets with 254 usable hosts in each.
How can you calculate the number of usable subnets for 192.168.1.192?
To calculate the number of usable subnets for the IP address 192.168.1.192, you first need to determine the subnet mask. Assuming a default Class C subnet mask of 255.255.255.0 (or /24), the address can be subnetted further. For example, if you use a /26 subnet mask (255.255.255.192), you can create 4 subnets (2^(26-24) = 4). Each of these subnets will have 62 usable IP addresses (64 total addresses minus 2 for the network and broadcast addresses).
How many Subnets can you create on a Class C address with the subnet mask being 255.255.255.192 the answer i got was wrong and I don't understand where I went wrong please help. Thank you?
192 is equal to 2 bits borrowed 2^2 = 4 the number of subnets and host are 64 because 2 bits borrowed from the 8 bits of a class C network is 6, therfore 2^6 = 64.
How do you create 8 subnets for 192.168.1.024?
To create 8 subnets for the IP address 192.168.1.0, you need to use subnetting. Since 8 subnets require 3 additional bits (as 2^3 = 8), you can take 3 bits from the host part of the default subnet mask (255.255.255.0 or /24). This will change the subnet mask to 255.255.255.224 (/27), allowing for 8 subnets, each with 30 usable host addresses (2^5 - 2 = 30). The resulting subnets will range from 192.168.1.0 to 192.168.1.224.
How many valid subnets do you get if you borrow 3 bits?
When you borrow 3 bits from the host portion of an IP address, you can create (2^3 = 8) valid subnets. However, one subnet is reserved for the network address and another for the broadcast address, leaving you with 6 usable subnets. Thus, by borrowing 3 bits, you obtain 6 valid subnets for use.
What subnet mask will be used to create 254 subnets on class b network?
To create 254 subnets in a Class B network, you need to borrow bits from the host portion of the address. Class B has a default subnet mask of 255.255.0.0 (or /16). To achieve 254 subnets, you need to use 8 bits for subnetting (2^8 = 256, minus 2 for network and broadcast addresses). This results in a new subnet mask of 255.255.255.0 (or /24), allowing for 254 usable subnets.
How many subnets are on a broadcast address of 205.61.128.64?
At least one.
