Kilobits = one thousand bits per second transmitted Megabit = one million bits per second transmitted
The maximum effect of a 2-ms burst of noise on data transmitted at 14 kbps can be calculated by determining how many bits are transmitted during that time. At 14 kbps, 2 ms corresponds to 28 bits (since 14,000 bits per second multiplied by 0.002 seconds equals 28 bits). Therefore, a 2-ms burst of noise could potentially disrupt up to 28 bits of data, impacting the integrity of the transmitted information depending on the error correction and detection mechanisms in place.
bus
Bandwidth
No, television signals are transmitted through radio waves rather than physical bits like those in computer data transmission. Television signals are encoded using a different method suitable for broadcasting audio and video content to TV sets.
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The maximum effect of a 2-ms burst of noise on data transmitted at 12 kbps can be calculated by determining how many bits are transmitted during that time. At 12 kbps, 2 ms corresponds to 24 bits (since 12,000 bits per second multiplied by 0.002 seconds equals 24 bits). Therefore, a 2-ms burst of noise could potentially corrupt or disrupt the transmission of up to 24 bits of data, depending on the nature of the noise and the error correction mechanisms in place.
The physical layer of the OSI model does not operate with a specific number of bits, as it deals with the transmission of raw binary data over physical media. Instead, it is concerned with the characteristics of the physical connection, including voltage levels, timing, and signaling methods. Data is transmitted as a series of bits, but the physical layer itself is focused on how these bits are represented and transmitted over the medium.
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In asynchronous transmission using a 6-bit code with two parity bits (one for each nibble), one start bit, and one stop bit, the total number of bits transmitted per codeword would be 10 bits (6 data bits + 2 parity bits + 1 start bit + 1 stop bit). This results in a data efficiency of 60% (6 bits of actual data out of 10 total bits). This means that for every 10 bits transmitted, only 6 bits are useful data, making it less efficient compared to systems with fewer overhead bits.
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BY USING FORMULA (M+R+1)<=2r 011110110011001110101 ---- The formula d + p + 1 <= 2^p (where d is the number of data bits and p is the number of check bits) indicates that we need at least 5 check bits in order to correct single-bit errors in blocks of 16 data bits -- a (21,16) code. SECDED requires 6 check bits for blocks of 16 data bits.