The rate of transfer of a process is equal to the driving force divided by the resistance.The mass transfer coefficient is the resistance to mass transfer. In mass transfer the driving force is the concentration gradient. The mass transfer coefficient is considered anything that contributes to resistance to mass transfer: thermal and eddy diffusivity, distance, etc.Fick's law of diffusion describes convective mass transfer as:N=-c*D*(ca2-ca1)/(z2-z1)where:-c is some constant multiplier (unitless)-The quantity (z2-z1) is the distance between two points. (length i.e. meters)-D is the mass diffusivity or the diffusion coefficient and is dependent on properties of the substance (such as particle size etc.) and temperature. (units: length2/time i.e. m2/s)-The quantity (ca2-ca1) is the concentration gradient between the same two points (the driving force) (units: amount/length3 i.e. mol/m3)-N is the rate of mass transfer (units: mass/(length2*time) i.e. mol/m2*s) )Putting Fick's law in terms of the mass transfer coefficient kc', yields:N=-kc'*(ca2-ca1)where kc'= -c*D/(z2-z1).You can see that the mass transfer coefficient is in fact a function of the diffusivity.
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The molar mass of copper is approximately 63.55 g/mol. This value corresponds to the average atomic mass of copper taking into account the isotopic abundances of its different isotopes.
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol
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These are not compatible. The first is Energy per Temperature. The second is Energy per amount of matter.
You have :N2 + O2 -----> 2NOmoles NO = ( 2 mols N2 reacted ) ( 2 mol NO / mol N2 reacted )moles NO = 4 moles NOmass NO = ( 4 mol NO ) ( 30 g NO / mol NO ) = 120 g NO
1 mol of octane (C8H18) reacts with 25 mol of oxygen (O2) to produce 8 mol of CO2 and 9 mol of H2O. Therefore, 0.74 mol of oxygen can react with 0.0744 mol of octane.
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
There are 3500 mmol in 3.5 mol. To convert mol to mmol, you multiply by 1000 since there are 1000 mmol in 1 mol.
To find the empirical formula, we need to determine the ratio of each element in the compound. First, find the moles of each element: K = 0.104 mol C = 0.052 mol O = 0.156 mol Next, divide each mole value by the smallest mole value to get the ratio: K = 0.104 mol / 0.052 mol = 2 C = 0.052 mol / 0.052 mol = 1 O = 0.156 mol / 0.052 mol = 3 Therefore, the empirical formula is K2CO3.
First, calculate the moles of each gas using their molar masses: He (4.0 g / 4.0 g/mol = 1.0 mol), Ar (6.5 g / 39.9 g/mol = 0.163 mol), Ne (10.0 g / 20.2 g/mol = 0.495 mol). Then, calculate the total moles of gas in the solution: 1.0 mol + 0.163 mol + 0.495 mol = 1.658 mol. Finally, find the mole fraction of He by dividing the moles of He by the total moles of gas: 1.0 mol / 1.658 mol ≈ 0.602.