Yes, this is good quantity and quality. Knowing the manufacture of the RAM listed above would be required for a more in depth answer.
64
4K (4096) of addressable space is defined by 12 bits of address space, because 212 = 4096.
to find the memory from address lines. you just have to make address liness power of 2, as shown below for 12 address lines 212 bits. 212 = 22 * 210 = 4 Kbthat means we can address 4 Kb from 12 address lines.........
The typical laptop has around 4 Gigabytes (4096 MB) of RAM memory.
4,096 In computer memory, "kilo" refers to 2 to the 10th power, or 1024, rather than to 1000.
You need 12 address lines to access 4K of memory. 212 = 4096. log2 (4096) = 12.
4096
The 2147 memory is 4096 X 1 bit static RAM. You need 8 chips to form 4K x 8.
15 bits
a) To provide a memory capacity of 4096 bytes using 256x8 RAM chips, you need 4096 bytes / 256 bytes per chip = 16 chips. b) Each memory address for the 256 locations in a chip will require 8 bits (since 2^8 = 256). Therefore, each chip will require 8 address lines to select one of the 256 locations.
The number of times eight can go in to 4096 is 512. 4096 divided by 8= 512
It is: 2 to the power of 12 = 4096