8085 is a 8 bit microprocessor and so A register which is also known as accumulator is also 8 bit.
A register pair typically consists of two registers, each of which can contain a specific number of bits, commonly 8, 16, or 32 bits, depending on the architecture. Therefore, the total number of bits in a register pair is double the bit width of a single register. For example, if each register is 16 bits, the register pair would contain 32 bits.
The 8085 has a 16 bit address bus.
The 8085 is an 8 bit processor, so its word length is 8 bits.
8 bits.
There are seven 8 bit registers in the 8085. A, B, C, D, E, H, and L
Generally, 8 bits at a time. Some instructions deal with 16 bit numbers.
24 bits are needed for the program counter. Assuming the instructions are 32 bits, then 32 bits are needed for the instruction register.
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.
8086 is a 16bit processor.
32 bit
We have only one flag register of 8 bits. Bits description is as follows (Assuming D0=LSB & D7=MSB) D7=Sign Bit. D6= Zero Flag D4= Auxiliary Carry Flag D2 = Parity Flag D0= Carry Flag.
The 8085 microprocessor has a 16-bit address bus and an 8-bit data bus. This means it can address up to 2^16 (or 65,536) memory locations, while it can transfer 8 bits of data at a time. The combination of these buses allows the 8085 to efficiently access and process data from memory.