16 bits per block . 8 16bit blocks = 128bits
16 bits per block
To create a subnet ID, you start with the network's base IP address and subnet mask. The subnet mask determines how many bits are allocated for the network and how many for the hosts. By applying the subnet mask to the base IP address, you can identify the subnet ID, which represents the network portion of the address. For example, if your base IP is 192.168.1.0 with a subnet mask of 255.255.255.0, the subnet ID is 192.168.1.0.
16 bits per block
The subnet mask would be 255.255.255.0
To determine the number of bits in the subnetted ID of 185.27.54.0, you need to know the subnet mask used. However, if it’s a standard Class B address (which uses a default mask of 255.255.0.0), it has 16 bits for the network portion. If the address is subnetted further, additional bits are borrowed from the host portion, increasing the network bit count. For example, if a subnet mask of 255.255.255.0 is used, then there would be 24 bits in the subnetted ID.
Subnet mask.
Since a subnet mask is used to separate the network id from the host id, any 1 bits indicate the network portion and the 0 bits indicate host portion. As an example, in the subnet mask: 255.255.0.0 This indicates the first two octets are used for the network, and the last two octets (ipV4) are used for host portion of an address.
It depends on the book, but is usually known as the extended network prefix.
151.242.16.49 would be class B in a classful environment with a network mask of 16 bits. An additional 7 bit subnet mask puts the total mask at 23 (i.e.: 255.255.254). Subnet ID would be: 151.242.16.0 Host address range: 151.242.16.1 through 151.242.17.254 Subnet Broadcast address would be: 151.242.17.255
Since this is a class B network you have borrowed 8 bits for subnets. This leaves 8 bits left (1 octet) for clients/workstations. That gives you a maximum of 254 clients per subnet.
The 1 bits indicate the use and presence of the network id information. 0 bits represent the location of client information.
You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.You must extract the first 8 bits of the host address (since the subnet mask has the first 8 bits equal to 1), and set all others to zero. The answer in this case is 86.0.0.0.