9
21 bits.
24 bits are needed for the program counter. Assuming the instructions are 32 bits, then 32 bits are needed for the instruction register.
There are 8 bits
8 bits if unsigned, 9 bits if signed
11 bits. 211 = 2048
how many bits are needed to represent decimal values ranging from 0 to 12,500?
Every bit can be either 0 or 1. Therefore 4 bits can encode a maximum of 42 = 16 digits.
5
1
18 in binary is 10010 Since 18 can't be written in term of 2 to the power x, the number of bits needed is 5. The answer is 5
A standard deck of playing cards has 52 cards. To determine how many bits are needed to represent each card, we can use the formula ( \lceil \log_2(52) \rceil ). Since ( \log_2(52) ) is approximately 5.7, we round up to 6 bits. Therefore, 6 bits are needed to uniquely represent each card in a standard deck.
1200