a void has no return statement. If that is what ur asking
/* -----a //- is space * -----ab * ----abc * --abcd * -abcde */ import java.io.*; class RevPyrA { protected static void man()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter the limit: "); byte a=Byte.parseByte(in.readLine()); for(byte i=0;i<a;i++) { System.out.println(); for(byte j=a;j>i;j--) System.out.print(" "); for(byte j=0;j<=i;j++) System.out.print((char)(97+j)); } }}
The Dreaming Void has 656 pages.
Void Moon has 407 pages.
You have to take a dump!
The answer to this will be platform and implementation dependent. For Windows machines, look into the keybd_event function: VOID keybd_event( BYTE bVk, // virtual key code BYTE bScan, // hardware scan code DWORD dwFlags, // special flags PTR dwExtraInfo // whether the key is pressed or released );
import java.io.*; class AvgWordSent { protected static void main()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter the Sentence: "); String s=in.readLine(); byte a=0,b=0; float c=0; for(byte i=0;i<s.length();i++) { if(s.charAt(i)==' ') a++; } String w[]=new String[a+1]; for(byte i=0;i<=a;i++) w[i]=""; for(byte i=0;i<s.length();i++) { if(s.charAt(i)==' ') { b++; continue; } w[b]+=s.charAt(i); } b++; for(byte i=0;i<=a;i++) c+=w[i].length(); System.out.print("Average no. of words= "+(c/b)); } }
172
/* Input: Do Your Duty * Output: Duty Your Do */ import java.io.*; class RevSent { protected static void main()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter the Sentence: "); String s=in.readLine(); char ch; short a=0,b=0; for(short i=0;i<s.length();i++) { ch=s.charAt(i); if(ch==' ') a++; } String w[]=new String[a+1]; for(short i=0;i<=a;i++) w[i]=""; for(short i=0;i<s.length();i++) { ch=s.charAt(i); if(ch==' ') b++; else w[b]+=ch; } for(short i=a;i>=0;i--) System.out.print(w[i]+" "); }}
You can get void armour in runescape by playing the mini game called "Pest Control" WARNING This may take some time to obtain.
import java.io.*; class sing { protected static void main()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); int a[]=new int[5]; for(byte i=0;i<5;i++) { System.out.print("Enter the value of "+i+" : "); a[i]=Integer.parseInt(in.readLine()); } byte b=0; for(byte i=0;i<5;i++) { if(b>a[i]) b=a[i]; } }}
Zero or more. Note: if zero, write void: int foo (void)