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What else can I help you with?
How many bytes in an address of an int variable?
32 bits or 4 bytes and an int is not an address, it is a primitive so it directly access the data without a reference.
What layer combines bits into bytes and bytes into frames and uses mac addressing?
Data Link
What is data items?
Unit of data contained in a record, describing a particular attribute (such as name, age, address) and requiring one or several bits, bytes, or words to represent an entity.
Are bits and bytes the same in terms of digital data storage?
No, bits and bytes are not the same in terms of digital data storage. A bit is the smallest unit of data and can have a value of either 0 or 1, while a byte is made up of 8 bits and can represent a larger range of values.
What's the difference between bits and bytes in terms of data storage and processing?
Bits and bytes are units of digital information. A bit is the smallest unit of data and can have a value of either 0 or 1. A byte is made up of 8 bits and is used to represent a single character or symbol. In terms of data storage and processing, bits are used for basic operations and calculations, while bytes are used to store and process larger amounts of data.
What is bits per seconds and bytes per seconds?
That usually refers to the rate of data transfer - how many bits, or bytes, can be transferred every second. It might also refer to some other data processing. Reminder: 1 byte = 8 bits.
The data hierarchy goes from bits and bytes to?
records, entities, fields, and databases.
How many address lines and data lines are required from 256K 16 memory system?
In a 256K x 16 memory system, the memory has 256K (256 * 1024 = 262,144) addressable locations and each location holds 16 bits of data. To calculate the number of address lines needed, we find the base-2 logarithm of 256K, which is 18 (since 2^18 = 262,144). For the data lines, since each location holds 16 bits, 16 data lines are required. Thus, the system requires 18 address lines and 16 data lines.
How many bytes are required to encode n bits of data where n equals 17?
1 bytes is 8 bits so (17/8) = 2.125 so round up to 3 full bytes
How many bytes are required to encode n bits of data where n equals 4?
One byte is 0.125 to 1 bit. So 4 bits, is .5 bytes.
How many bits are there in a data link layer Ethernet address?
How many bits are there in a data link layer ethernet address?
How many bytes are required to encode 500 bits of data?
62.5
