The number of bytes required to store a number in binary depends on the size of the number and the data type used. For instance, an 8-bit byte can store values from 0 to 255 (or -128 to 127 if signed). Larger numbers require more bytes: a 16-bit integer uses 2 bytes, a 32-bit integer uses 4 bytes, and a 64-bit integer uses 8 bytes. Thus, the number of bytes needed corresponds to the number of bits needed for the binary representation of the number.
The number of digits required to store a number in binary is substantially greater than that required in octal and even larger than in hex.
To determine how many bytes are needed to represent the number 2501, we first convert it to binary. The binary representation of 2501 is "10011100001," which requires 12 bits. Since one byte is 8 bits, you would need 2 bytes (16 bits) to store the value 2501.
four
how many bytes are there in a 64-bit machine? Another Answer: It takes 8 bytes to store a 64 bit number.
4
A letter is stored in binary on a computer. The word summer in binary is written as: 011100110111010101101101011011010110010101110010. That's 48 digits. There are 8 bits in 1 byte, thus 48/8 = 6. So 6 bytes are used to store summer. On modern computers, each character in the English alphabet is represented by a byte. Therefore the word SUMMER takes up 6 bytes of memory.
how many bytes are there in a 64-bit machine? Another Answer: It takes 8 bytes to store a 64 bit number.
40 bits or 5 byrtes
You only need one bit to denote 0 or 1... so 1/8th of a byte would be enough. The actual space taken to store the number 1 would be defined by the type of the variable that is holding the number... if you were programming in C, and used the integer type to store the value 1, it would use 2 bytes - those two bytes, in binary, would read 0000000000000001.
about eight bits, which is equal to one byte
The word "intelligent" consists of 11 characters. In standard encoding, such as UTF-8 or ASCII, each character typically requires 1 byte. Therefore, to store the word "intelligent," 11 bytes are required.
To store the hexadecimal number FF, we need to convert it to binary first. FF in hexadecimal is equivalent to 1111 1111 in binary, which requires 8 bits to represent. Each hexadecimal digit corresponds to 4 bits in binary, so two hexadecimal digits (FF) require 8 bits to store.