65,536
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
There are 256 possible values (or characters) in 8 bits.
Four bytes can store (2^{32}) different values, since each byte consists of 8 bits and 4 bytes equal 32 bits. This means that the total number of unique combinations is (2^{32} = 4,294,967,296). This range includes values from 0 to (4,294,967,295) for unsigned integers, or from (-2,147,483,648) to (2,147,483,647) for signed integers.
2^12=4096
0 o 1
The size of a byte is typically hardware dependent, but the modern standard is eight bits. 8 bits can store 255 different values and this is enough to store one keyboard character. Therefore one byte can store one character of a text message.
I assume you mean "stored". In each case, a total of 2 to the power 13 different numbers can be stored.
To find out how many different values can represented by a certain number of bits, we can use the following formula 2n-1 and that is because the first number is always a zero.Based on that 6 bits = 26- 1= 64-1=637 bits= 27-1= 1278 bits= 28-1=25510 bits= 210-1=1023# of bits1=12=33=74=155=316=637=1278=2559=51110=1023
Eight bits to the octet. The values are 0-255.
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
16 bits. Java char values (and Java String values) use Unicode.