65,536
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
There are 256 possible values (or characters) in 8 bits.
2^12=4096
0 o 1
Eight bits to the octet. The values are 0-255.
To find out how many different values can represented by a certain number of bits, we can use the following formula 2n-1 and that is because the first number is always a zero.Based on that 6 bits = 26- 1= 64-1=637 bits= 27-1= 1278 bits= 28-1=25510 bits= 210-1=1023# of bits1=12=33=74=155=316=637=1278=2559=51110=1023
The size of a byte is typically hardware dependent, but the modern standard is eight bits. 8 bits can store 255 different values and this is enough to store one keyboard character. Therefore one byte can store one character of a text message.
I assume you mean "stored". In each case, a total of 2 to the power 13 different numbers can be stored.
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
16 bits. Java char values (and Java String values) use Unicode.
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
16 bits per block