32 values. 2^5=32
There are 256 possible values (or characters) in 8 bits.
8192
A binary system can represent two distinct states, typically denoted as 0 and 1. Each bit in a binary system can hold one of these two values. When multiple bits are combined, the number of distinct states increases exponentially; for example, an n-bit binary system can represent 2^n distinct states.
1200
how many bits are needed to represent decimal values ranging from 0 to 12,500?
To represent 63 values, you need at least 6 bits, as 2^6 = 64, which can accommodate all 63 values. However, if you're specifically using 8 bits per value, then you would use 8 bits for each of those 63 values, resulting in a total of 63 x 8 = 504 bits.
A bit represents two colors or states, typically represented as 0 and 1. In digital systems, these can correspond to different colors or signals, but fundamentally, a single bit can only convey two distinct values. When multiple bits are combined, they can represent a broader range of colors; for example, 8 bits can represent 256 different colors.
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
2 raised to the 8th power, or "2^8", or 256.
To represent 64 characters, you would need 6 bits. This is because 2^6 equals 64, meaning six bits can encode 64 different values, sufficient for each character. Each bit can represent two states (0 or 1), and with six bits, you can create combinations to represent all 64 characters.
The number of distinct combinations that can be created with n bits is 2n.
With 5 bits, you can represent (2^5) different numbers, which equals 32. This includes numbers ranging from 0 to 31 in unsigned binary representation. If using signed binary representation (like two's complement), the range would be from -16 to 15, still allowing for 32 distinct values.