32 values. 2^5=32
There are 256 possible values (or characters) in 8 bits.
8192
A binary system can represent two distinct states, typically denoted as 0 and 1. Each bit in a binary system can hold one of these two values. When multiple bits are combined, the number of distinct states increases exponentially; for example, an n-bit binary system can represent 2^n distinct states.
1200
how many bits are needed to represent decimal values ranging from 0 to 12,500?
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
2 raised to the 8th power, or "2^8", or 256.
The number of distinct combinations that can be created with n bits is 2n.
With 5 bits, you can represent (2^5) different numbers, which equals 32. This includes numbers ranging from 0 to 31 in unsigned binary representation. If using signed binary representation (like two's complement), the range would be from -16 to 15, still allowing for 32 distinct values.
A 4-bit binary number can represent (2^4 = 16) different values. This range includes all combinations of 0s and 1s that can be formed with four bits, ranging from 0000 (0 in decimal) to 1111 (15 in decimal). Thus, the values it can represent are 0 through 15.
8 bits if unsigned, 9 bits if signed
Eight bits to the octet. The values are 0-255.