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The 2010 Kenworth T660 typically requires about 10 to 12 gallons of antifreeze, depending on the engine configuration and cooling system. It's important to refer to the owner's manual or consult with a mechanic for the exact specifications for your particular vehicle. Additionally, ensure that you use the appropriate type of antifreeze recommended for your engine.
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How many gallons of antifreeze in a 2000 Blazer radiator?
how many gallons of antifreeze in a 2003 blazer radiator with a/c
How many gallons of antifreeze for semi tractor?
It would take approximately 12 gallons of antifreeze to fill a semi tractor.
How many gallons of a 50 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 40 percent antifreeze?
70gallons
How many gallons of a 90 percent antifreeze solution must be mixed with 80 gallons of 25 percent antifreeze to get a mixture that is 80 percent antifreeze?
614
How many gallons of a solution that is 75 antifreeze must be mixed with 4 gallons of a 30 solution to obtain a mixture that is 50 antifreeze?
You will need 3.2 gallons.
How many gallons of antifreeze does a 1998 Mercury Sable hold?
2.6 gallons
How many gallons of a 80 percent antifreeze solution must be mixed with 60 gallon of 15 percent antifreeze to get a mixture that's 70 percent antifreeze?
330 gallons of 80% antifreeze mixed with 60 gallons of 15% antifreeze will provide 390 gallons of 70% antifreeze. Let the multiplier of 60 gallons be x, then considering the percentages of antifreeze in the solutions: (15 + 80x) ÷ (1 + x) = 70 ⇒ 15 + 80x = 70 + 70x ⇒ 10x = 55 ⇒ x = 5.5 Therefore mix 60 x 5.5 = 330 gallons of 80% antifreeze.
How many gallons of a 80 percent antifreeze solution must be mixed with 70 gallons of 20 percent antifreeze to get a mixture that is 70 percent antifreeze?
70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.
How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 10 percent antifreeze to get a mixture that is 40 percent antifreeze?
Let X = gallons of 50% antifreeze .5X + .1(70) = .4 (X + 70) .5X + 7 = .4X + 28 .1X = 21 X = 210 GALLONS
How many gallons of a 80 percent antifreeze solution must be mixed with 90 gallons of 25 percent antifreeze to get a mixture that is 70 percent antifreeze?
Let X = gallons of 80% antifreeze Then 0.80X + .25 (90) = .70( 90 + X) .80X + 22.5 = 63 + .70X .1X = 41.5 X = 415 gallons
How many gallons of a 90 percent antifreze solution must be mixed with 90 gallons of 10 percent antifreeze to get a mixture that is 80 percent antifreeze?
630
How many gallons of antifreeze must be mixed with 70 gallons of 25 percent antifreeze to get a mixture that is 80 percent antifreeze?
Find the overall balance of antifreeze: amount of antifreeze to start with + the amount of pure antifreeze to add = amount of antifreeze in the final solution Let X be the amount of pure antifreeze to add in gallons. (70 * 0.25) + X = 0.80 * (70+X) 17.5 + X = 56 + 0.8X 0.2X = 56 - 17.5 0.2X = 38.5 X = 38.5/0.2 = 192.5 gallons
