How many gallons of water in a 18x48 pool?

Answer 1

The answer to this question will require some simple dimensional analysis and geometry.

Assuming that he pool is a round above ground pool, 18 feet in diameter and 48 inches deep you first need to calculate the area of the swimming pool in square inches and then multiply by the depth in inches to get the volume in cubic inches:

The pool is an 18 foot diameter circle.

The diameter in inches of the 18 foot pool is 216 inches (18 feet x 12 inches / foot)

The area of a circle = pi (3.1415) x radius x radius

The radius = 1/2 of the diameter

The area of an 18 foot diameter pool in square inches is:

3.1415 * 108 inches * 108 inches = 36643.5 square inches

The volume in cubic inches of an 18 foot diameter pool is:

36643.5 square inches x 48 inches = 1758890 cubic inches.

There are 231 cubic inches in one gallon so the volume of an 18 foot diameter, 48 inch deep pool is:

1758890 / 231 = 7,614 gallons

If it is a square or rectangular pool simply multiply the length x the width x the average depth.

Answer 2

18' round x 3-1/2' deep will hold 6,600 - 6,700 US gal

Answer 3

Cannot be answered with only these measurements. For a rectangular pool, the length, width and depth are needed. For a round pool, the diameter and depth are needed.

Answer 4

A P R 2376 gallons

Answer 5

Not enough information.

Answer 6

Approximately 8119 gallons!