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The complete combustion of glucose (C6H12O6) produces carbon dioxide (CO2) and water (H2O). The balanced chemical equation is: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O. From this, we see that 1 mole of glucose produces 6 moles of CO2. Since the molar mass of glucose is approximately 180 g/mol, 126 grams of glucose corresponds to 0.7 moles. This will yield 0.7 moles × 6 moles CO2/mole glucose = 4.2 moles of CO2. At standard temperature and pressure (STP), 1 mole of gas occupies 22.4 liters, so 4.2 moles of CO2 will produce approximately 94.08 liters of CO2.

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2mo ago

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The balanced chemical equation for the reaction is: C6H12O6 + 6O2 -> 6CO2 + 6H2O The molar mass of glucose is 180 g/mol, so 126 g of glucose is 0.7 moles. From the equation, 1 mole of glucose produces 6 moles of CO2, so 0.7 moles of glucose will produce 4.2 moles of CO2. Using the ideal gas law, at STP conditions, 4.2 moles of CO2 will occupy 94.5 liters.