About 7,570.824 mL is needed to equal two US gallons.
3/32 gallons = 1.5 cups.
Let x represent the gallons of 10% ammonia solution. The total volume of the mixture is x + 50 gallons. The equation for the mixture is: 0.10x + 0.30(50) = 0.15(x + 50). Solving this equation gives x = 50 gallons of the 10% ammonia solution needed.
To make a 1% solution, you would need to mix the pint of herbicide with 7.5 gallons of water.
Let x represent the amount of 12% solution and (10-x) represent the amount of 20% solution. The equation to solve is: 0.12x + 0.20(10-x) = 0.14(10). Solving for x gives x = 4, so you need 4 gallons of the 12% solution and 6 gallons of the 20% solution to make 10 gallons of the 14% solution.
25 gallons
Let x be the gallons of the 80% acid solution needed. The amount of acid in the 80% solution is 0.8x, and the amount in the 16% solution is 0.16*60=9.6. We want a total of (x+60) gallons of solution with 60% acid, so we have the equation 0.8x + 9.6 = 0.6(x+60). Solving for x gives x = 24 gallons.
To calculate the amount of chemical needed per gallon, first determine the total amount of chemical in the 5 gallons of water. Since 16 ounces in 5 gallons equal 500 ppm, you can set up a proportion: (16 ounces/5 gallons) = (x ounces/1 gallon). Solve for x to find out how many ounces of chemical are needed per gallon.
To make 10 gallons of a 50% sodium hydroxide solution, you would need 10 pounds of sodium hydroxide. This is because the percentage indicates the weight of sodium hydroxide in the solution. Hence, in a 50% solution, half of the weight of the solution is sodium hydroxide.
You will need 3.2 gallons.
50 gallons @ 3% must be added.
The answer is 7,5g.
You need 6,9 mL stock solution.