A subnet with a prefix of /100 indicates that the first 100 bits of the IP address are fixed for the network portion. However, since IPv4 addresses are only 32 bits long, a subnet mask of /100 is not valid in this context. In IPv6, which allows for longer prefixes, a /100 subnet would have 100 bits dedicated to the network, leaving 28 bits for host addresses.
To determine the number of Hamming bits needed for a 100-bit message, we can use the formula (2^r \geq m + r + 1), where (m) is the number of data bits (100 in this case) and (r) is the number of Hamming bits. Solving this inequality, we find that 7 Hamming bits are needed, as (2^7 = 128) satisfies (100 + 7 + 1 = 108). Thus, for a 100-bit message, 7 Hamming bits are inserted.
The number of bits in a message depends on its size and the encoding used. For example, if a message contains 100 characters and uses standard ASCII encoding, it would consist of 800 bits (100 characters x 8 bits per character). In general, to determine the total bits, multiply the number of characters by the number of bits per character based on the encoding scheme.
To determine the minimum number of bits needed to store 100 letters and symbols, we first need to consider the total number of unique characters. Assuming we use the standard ASCII set, which includes 128 characters (letters, digits, and symbols), we can represent each character with 7 bits. Therefore, to store 100 characters, we would need a minimum of 700 bits (100 characters × 7 bits per character). However, if a larger character set like UTF-8 is used, it may require more bits for some characters.
7 bits can show all 128 possible arrangements of 'yes' and 'no'. 6 bits can show only 64 possibilities.
To determine the number of bits in three dollars, we need to first convert the dollar amount to cents, as there are 100 cents in a dollar. Three dollars is equal to 300 cents. Next, we need to calculate the number of bits in 300 cents. Since 2^8 (256) is the closest power of 2 to 300, we would need at least 8 bits to represent 300 cents accurately.
i think it might be 8 bits to a bite not 100 percent though
Here is how you calculate that. 10MB is 10 million bytes (more precisely, 10 x 1024 x 1024). Multiply that by 8 to convert to bits (since bandwidth is measured in bits per second). gbps means billions of bits per second. Now divide the total number of bits by the bandwidth (in bits/second). The result is the number of seconds it takes.
1 mbps (mega bits per second) = 1000 kbps (kilo bits per second) as defined by IEEE. So, 100 mbps = 100,000 kbps.
ATA/ATAPI-6ATA/100 or ATA/ATAPI-6
Three of the bits are already determined. That leaves 5 .25 = 32
To convert a binary number to an octal number, you need to know how an octal number is represented in binary. It is like this: 0 = 000 4 = 100 1 = 001 5 = 101 2 = 010 6 = 110 3 = 011 7 = 111 As you can see, an octal number consists of 3 'bits' (either a 0 of a 1). Now, to convert a binary number to an octal number, you first have to group the binary digits into groups of 3 bits (starting from the right). Then, you convert every group of bits into octal numbers. This way you get your binary number into an octal one. For example: (1010100111010010)2 We group them into groups of 3 bits, starting from the right. 1 010 100 111 010 010 As you see, we have a single digit left. We must add 0's to make it a group of 3 bits. 001 010 100 111 010 010 Then we convert every group into an octal number, according to the table above. 001 = 1 010 = 2 100 = 4 111 = 7 010 = 2 010 = 2 And in this way, you converted a binary number into an octal one. (1010100111010010)2 = (124722)8
A pyramid with a polygonal base has as many edges as the number of sides of its base plus the number of edges in the base. A 100-gon pyramid would have 100 edges on its base and an additional number of edges equal to the number of sides of the base, which is also 100. Therefore, a 100-gon pyramid would have 100 + 100 = 200 edges.