Answer is, I think, 6 factorial, usually written 6!, which means 6x5x4x3x2x1, which is 120. This is the total number of different combinations of 6 digits. This answer is true if all six digits are always used. If it is allowed to use not all 6 digits, then the answer would be 6!+5!+4!+3!+2!+1!
This is 620+120+24+6+2+1, or 773.
Am I right? I left school 37 years ago, did maths A level in the UK but most of it is now forgotten!
There are 16 decimal numbers that can be represented by 4-bits.
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
1000
8 bits = 64 character
Binary bits are necessary to represent 748 different numbers in the sense that binary bits are represented in digital wave form. Binary bits also have an exponent of one.
It depends which dictionary, doesn't it? Shakespeare was responsible for inventing many words which were not previously recorded, and for using many words in ways not previously recorded. Estimates of the numbers vary.
With 5 bits, you can represent (2^5) different numbers, which equals 32. This includes numbers ranging from 0 to 31 in unsigned binary representation. If using signed binary representation (like two's complement), the range would be from -16 to 15, still allowing for 32 distinct values.
256 (0 through 255)
If you are using the ASCII system, the word "duck", as it has four letters, contains 4 bytes, or 32 bits.
Generally, 8 bits at a time. Some instructions deal with 16 bit numbers.
256 in total - including zero.
Every bit can be either 0 or 1. Therefore 4 bits can encode a maximum of 42 = 16 digits.