To determine the number of subnets created for the host IP 195.70.16.93, you need to know the subnet mask. Without this information, it's impossible to provide a specific number of subnets. Generally, subnetting involves dividing a larger network into smaller ones by borrowing bits from the host portion of the address, which can vary based on the chosen subnet mask. If you provide the subnet mask or CIDR notation, I can give a more precise answer.
3
14 (+2 for network & host).
5 bits are necessary to create up to 30 subnets.
you need to reallocate 4 bits to creat 16 subnets. how do I get that? easy! 2 to the power of 4 gives us 16 subnets.
There are 16 bits available; it is up to you how many of those bits you reserve for the subnet, and how many for the individual hosts within each subnet.
To create 6 subnets from the IP address 172.16.0.0, you need to determine how many bits to borrow from the host portion of the address. Since 2^3 = 8, borrowing 3 bits allows for 8 subnets, which is sufficient for your requirement of 6. This results in a subnet mask of 255.255.248.0 (or /21), providing each subnet with 2046 usable host addresses. The subnets would range from 172.16.0.0/21 to 172.16.7.0/21.
When you borrow 3 bits from the host portion of an IP address, you can create (2^3 = 8) valid subnets. However, one subnet is reserved for the network address and another for the broadcast address, leaving you with 6 usable subnets. Thus, by borrowing 3 bits, you obtain 6 valid subnets for use.
1
There are 65,536 subnets available in an IPv6 /48 block.
A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.Number of subnets is given by the formula : 2^(no. of bits used from host part).Hence number of subnets in this case would be = 2^2 = 4.For e.g. if the class C IP address is 200.168.210.0the 4 subnet addresses would be :11001000.10101000.11010010.00000000 = 200.168.210.011001000.10101000.11010010.01000000 = 200.168.210.6411001000.10101000.11010010.10000000 = 200.168.210.12811001000.10101000.11010010.11000000 = 200.168.210.192Note: The digits in bold are the mask bits.
3
At least one.