that depends on th type of sand
About 41 pounds.
Sand needed: 8*6*1.5 = 72 cubic feet
Volume of sand required = 7 ft * 7 ft * 1/6 ft = 49/6 cubic feet = 8.166... cubic ft.
137.5 cubic feet or 5.09 cubic yards.
270-ft x 1/2-ft = 135 cubic ft = 5.0 cubic yards
The answer depends on the grain size, lithology, moisture content, and level of compaction of the sand. Generally, one cubic ft of clean (no silt/clay), dry, fine to medium sand that has been compacted to a dense, non-yielding condition will weigh about 110 lbs., while a loose fine to medium sand will weigh about 100 lbs. per cubic foot.
12 ft * 10 ft * 10/12 ft = 10 cubic feet.12 ft * 10 ft * 10/12 ft = 10 cubic feet.12 ft * 10 ft * 10/12 ft = 10 cubic feet.12 ft * 10 ft * 10/12 ft = 10 cubic feet.
The answer will depend on how thinly the sand is spread.
This is a volume calculation. I assume the dimension for the "6" is inches? If so, the volume= 20x20x0.5= 200 cubic ft.= 7.4 cubic yards
Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.
That would take 250 cubic meters of sand to fill as 10*5*5 is 250.
8ft Wide by 8ft Long by 1ft Deep is 64sq/ft. A yard of sand is 36sq/ft. You will need a little less than 2sq/yards (72sq/ft). -------------------------------------------------------- We're talking about volume, not area, so 8x8x1 = 64 cubic feet, not sq. ft. A "yard" of sand actually means a cubic yard and is 3ft x 3ft x 3ft = 27 cubic feet, not 36 sq/ft. So you need 64/27 or a little over 2 1/3 cubic yards of sand.