1000 liter methanol = 1000 kg
1 liter metahnol = 1 kg
1 ml metahnol = 1 gram
10 ml metahanol = 10 grames
To prepare a 10 ppm (parts per million) calibration gas in 100 mL of nitrogen, you need to calculate the amount of methanol required. Since 10 ppm means 10 mg of methanol per liter of gas, for 100 mL (0.1 L), you would need 1 mg of methanol. To achieve this, you can directly weigh out 1 mg of methanol and dilute it in the 100 mL of nitrogen.
To solve this question you need to use the formula, density = mass/volume. So the equation would be 0.79 = mass/589mL. The answer is 465g.
With 25ml methanol and 75ml water, there is 100ml in total. So there is 25/100 = 25% by volume methanol.
The mass of 10 mL of water is 10 g.
To make a 100 ppm solution of methanol in 100 mL of water, you would need 10 mg of methanol. This is because 100 ppm is equivalent to 100 mg/L, and since you have 100 mL of water, you would need 10 mg of methanol (100 mg/L x 0.1 L).
In order to determine the amount of heat energy required, you first need to calculate the mass of 250.0 ml of methanol using the density provided (ρ = 0.787 g/ml). Mass = Volume x Density. Once you have the mass, you can use the molar enthalpy of vaporization value to determine the heat energy required using the formula: Heat energy = mass (in mol) x molar enthalpy of vaporization.
The final percent concentration of the solution would be approximately 12.0% methanol. This is calculated by dividing the volume of methanol by the total volume of the solution (600 ml / 5000 ml) and then multiplying by 100 to get the percentage.
Methanol, CH4O, has a molar mass of 32g (12g+4.0g+16g)* *note this is only rounded to two sig figs, since the mass of elements are usually rounded to the tenths place. Next, simply use dimensional analysis: 1ml/22.4L X 32g. you should get the right answer by doing the steps shown above.
Density = mass/milliliters Density = 10 grams/2 ml = 5 g/ml ---------------
The number of milliliters to have a mass of 238 g depends upon the mass density of the substance. For pure water at 4.0 C : ----------------------------------- d = 1.000 g per mL d = m / V ..... [ By Definition of mass density ] V = m / d = ( 238 g ) / ( 1.000 g /mL ) = 238 mL <------- For methanol at 10 C : --------------------------- d = 0.801 g / mL V = m / d = ( 238 g ) / ( 0.801 g / mL ) = 297 mL <-----------
25%
Density is calculated by dividing the mass of a substance by its volume. In this case, if the mass of the liquid is 10 grams and it occupies a volume of 1 mL, the density would be 10 grams per 1 mL, or simply 10 g/mL.