A 4-ft diameter pipe holds approx 78.3 US gallons.
A round pool with a 10-foot diameter and a 3-foot depth can hold up to 1,762 gallons of water.
A standard 50-foot garden hose with a diameter of about 5/8 inch can hold approximately 9-10 gallons of water when fully filled. This volume may vary slightly depending on the hose's diameter and design. Generally, the larger the diameter, the more water it can hold.
Over 9,000.
A 24-inch diameter cylinder holds 23.5 gallons of water per foot of length/height.
66 gallons
One foot of 3 inch pipe will hold approximately 0.625 gallons of water.
A 12 inch diameter round pipe will hold 4.89 UK gallons or 5.88 US gallons per foot.
Filled to the top, this well would hold about 956 gallons of water.
Do you mean a cylinder with a diameter of 5 feet and length of 12 feet? This would hold about 235.6 cubic feet or 1762.5 gallons
A 5-inch pipe will hold approximately 0.36 gallons of water per linear foot. This calculation is based on the formula for calculating the volume of a cylinder (V = πr^2h), where the radius (r) is half the diameter of the pipe (2.5 inches) and the height (h) is 1 foot.
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
To determine how much water a 4-foot culvert will hold, you need to know its shape and dimensions. A common cylindrical culvert with a 4-foot diameter will have a volume calculated using the formula for the volume of a cylinder: ( V = \pi r^2 h ), where ( r ) is the radius (2 feet for a 4-foot diameter) and ( h ) is the length of the culvert. For example, if the culvert is 10 feet long, it would hold approximately 125.66 cubic feet of water. To convert this to gallons, multiply by 7.48 (since 1 cubic foot is about 7.48 gallons), resulting in around 941 gallons.