The way that I solved it involves factorials (!) which is usually allowed. Factorials are definited as the product of that number and all of the numbers less than it, down to 1.
So, 4!=4*3*2*1=24.
In this case, 19=4!-4-(4÷4)
Ta da!
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
4+4(4-4)
101
4 /5
44 + 4/4
(4!/4)4 - 4
(4+4)/4 + 4 =6
-4-4+4/4
(4*4)-(4/4)
There are six fours in twenty-four.
4 x 4 + 4/4 = 17
4 x 4! - (4/.4)