The way that I solved it involves factorials (!) which is usually allowed. Factorials are definited as the product of that number and all of the numbers less than it, down to 1.
So, 4!=4*3*2*1=24.
In this case, 19=4!-4-(4÷4)
Ta da!
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
4+4(4-4)
101
4 /5
44 + 4/4
(4!/4)4 - 4
To make 11 using four fours, you can use the following equation: ( 4 \times 4 - 4 - 4 = 11 ). Here, you multiply two fours to get 16, then subtract two fours to reach 11. This creatively utilizes the four fours while adhering to the mathematical operations allowed.
(4+4)/4 + 4 =6
-4-4+4/4
(4*4)-(4/4)
There are six fours in twenty-four.
fourteen take away four and then add a four and times by (2 times 4)