CO NH refers to carbon monoxide (CO) and ammonia (NH₃). Carbon monoxide is a colorless, odorless gas produced by the incomplete combustion of carbon-containing fuels, and it can be toxic at high levels. Ammonia is a colorless gas with a pungent odor, commonly used in fertilizers and cleaning products. Both compounds are important in various industrial processes and environmental considerations.
Hydrogen, Carbon, Oxygen, Nitrogen Molecular formula [-CO-C6H4-CO-NH-C6H4-NH-]n
The chemical formula for NH is ammonia (NH₃) and the chemical formula for CO is carbon monoxide. When they react, they form the compound HCN (hydrogen cyanide).
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[NH- C -CO]n | R
An acetylamino is the univalent radical CH3-CO-NH- derived from acetamide.
Nylon-46 is generally synthesized from 1,4-diaminobutane and adipic acid. Nylon-46 has a symmetrical molecular structure and a fairly high amide content with the formula, -(NH-(CH2)4-NH-CO-(CH2)4-CO-)n
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Nylon is a generic name for a synthetic linear polymer with repeating amide groups (-NH-CO-) which is used in the manufacture of textile fibres. Carothers produced Nylon 66 by condensation reaction of adipic acid (a dicarboxylic acid with 6 carbon atoms) and hexamethylenediamine (a diamine with 6 carbon atoms) give the [-NH-(CH2)6-NH-CO(CH2)4-CO-] repeating unit. Nylon revolutionised the textile industry and was the forerunner for many of today's modern, synthetic fabrics.
The net charge is 0. First, lets look at the two amino acids separately. For Lys, you have: pka1=2.2 (coo-) pka2=9.1(NH2+) pka3=10.5 (lateral chain) For glu, you have: pka1=2.1(COO-) pka2=4.1 (lateral chain) pka3=9.5(NH2+) First, below 2.1: 100% of : NH2+---------CH----CO-NH---CH-----COOH (CHARGE=2+) COOH NH+ At 2.1: 50% of :NH2+---------CH----CO-NH---CH-----COOH COOH NH+ 50% of :NH2+---------CH----CO-NH---CH-----COOH (here, we see that there was no COOH NH+ change, WHY: the carboxyl of glu should be ionized at 2.1, but it is attached to the amino group of lys, so there is no change At 2.2 ...of NH2+---------CH----CO-NH---CH-----COO- (charge+1) COOH NH+ At 4.1 ....of NH2+---------CH----CO-NH---CH-----COO- (CHARGE=0) COO- NH+ At pI = 6.8 100 % of NH2+---------CH----CO-NH---CH-----COO- (CHARGE=0) COO- NH+ Since the next pka is at 9.1, we don't have any change yet at the physical pH 7.4. Thus, the charge is zero. I didn't put the pI in between b4, it would just take too much time, but I hope that you do understand the concept now. Good luck