1/a + 1/b = b/ab + a/ab = (b+a)/ab So, the answer to your question is 32/48 or 2/3
It could be a vector sum.
ab+bc+ca
ranges evaluated
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
If you use Excel in school, then, yes, you can use the SUM function.
The average of a set of numbers is equal to the sum of those numbers divided by the number of numbers. So, one might say that the average function is equal to the sum function divided by the count function.
The sum of two cubes can be factored as below.a3 + b3 = (a + b)(a2 - ab + b2)
The SUM function. You could also do it with the SUBTOTAL function, but the SUM function is the best one to use.
AB + BC = AC The sum of the parts equals a whole :]
a3+ b3 = (a + b)(a2 - ab + b2)
(a3 + b3) = (a + b)(a2 - ab + b2)