The function of the absolute sum, often represented as ( \text{abs}(a) + \text{abs}(b) ), is to calculate the total magnitude of two values, ( a ) and ( b ), regardless of their signs. This function is useful in various mathematical and computational contexts, such as optimization problems and data analysis, where the direction or sign of values is less important than their overall size. By summing the absolute values, it ensures that all contributions are considered positively.
If the difference of AB and the difference of BC is 98, it can be expressed mathematically as ( AB - BC = 98 ). To find the sum of AB and C, we need more information about the values of AB and BC. Without additional details about the relationships between AB, BC, and C, we cannot determine the exact sum of AB and C.
1/a + 1/b = b/ab + a/ab = (b+a)/ab So, the answer to your question is 32/48 or 2/3
It could be a vector sum.
ab+bc+ca
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
ranges evaluated
The sum of two cubes can be factored as below.a3 + b3 = (a + b)(a2 - ab + b2)
If you use Excel in school, then, yes, you can use the SUM function.
The average of a set of numbers is equal to the sum of those numbers divided by the number of numbers. So, one might say that the average function is equal to the sum function divided by the count function.
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
a3 + b3 = (a + b)*(a2 - ab + b2)anda3 - b3 = (a - b)*(a2 + ab + b2)