Since period is the reciprocal of frequency, i.e Period = 1/frequency:
Frequency = 4 kHz = 4000 cycles/sec
Period = 1/(4000 cycles/sec) = 1 sec/4000 cycles = 0.00025 sec/cycle
Period = (1/frequency) = 1/104 = 10-4 = 0.0001 second = 0.1 millisec = 100 micro sec.
Period = 1/frequency = 1/250 = 0.004 = 4 milliseconds
The frequency of the wave is the reciprocal of the period, so in this case, it would be 1/4 Hz.
Frequency = 1/period = 1/0.25 = 4 Hz.
1/4
Frequency = 1 / (period) = 1/.4 = 2.5 Hz
If 10 V input causes a frequency shift of 4 kHZ then 2,5v causes a freuency shift of 1 kHz. The input signal frequency of 1 kHz is irelevant.
4 Hz
Wave B has the higher frequency because frequency is the inverse of period. Mathematically, frequency = 1/period. Comparing the two periods, Wave B's period is smaller, so its frequency is higher.
The period of the wave is 4 seconds, as it takes 4 seconds to complete one full cycle (rise and fall). The frequency of the wave is 0.25 Hz, as it completes two cycles (rises and falls) in 4 seconds. Frequency is the reciprocal of period, so 1/4 = 0.25 Hz.
4Hz because this wave happens 4 times per second. Hz=1second / frequency.
1/4 Hz.