Yes, it can store any number from 0 to 255. It is also capable of storing numbers down to -127. There are 8 bits in a byte, each of which can store 0 or 1. They represent powers of 2. So 8 bits could be 11111111, which is a binary number and can be thought of as representing a number this way:
One 128.
One 64.
One 32.
One 16.
One 8.
One 4.
One 2.
One 1.
If you add those up you get 255.
255 is the largest decimal number. 1 byte (8 bits) can store 256 *values* (0-255).
Yes, it can store any number from 0 to 255. It is also capable of storing numbers down to -127. There are 8 bits in a byte, each of which can store 0 or 1. They represent powers of 2. So 8 bits could be 11111111, which is a binary number and can be thought of as representing a number this way:One 128.One 64.One 32.One 16.One 8.One 4.One 2.One 1.If you add those up you get 255.
Since 8 bits = 1 byte, the maximum value it could have can be found when all 8 bits are "turned on" or are 1's. 1111 1111 = 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = 255
byte has 8 bits all bits at 0 = zero all bits at 1 = 255
1 byte = 8 bits from 00000000 (00) to 11111111 (FF) = 0 to 255 or 256 values
1 byte is made up of 8 bits.In Binary 8 bits have a value of 0-255, therefore any character in ASCII will only take up a physical space of 1 byte.
11111111 (base 2, also called biinary) represents 255. This is all 8 bits of a byte have a value of 1. A byte can represent 256 different values (0 to 255)
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
it depend on the language which are you using if it is c than 1 bytes if it is java than 2 bytes and vary for the languages but it is generally either 1 or 2 1 byte =8 bit
97 = 0 1 1 0 0 0 0 1
AnswerAn unsigned char is a byte; its value can be between 0 and (2^8) - 1 (i.e., 0-255).
It can't. The maximum value of a single byte is 255.