Radius ratio of FCC is 1.0 and of BCC is 0.732
FCC has a higher packing efficiency and the slip planes are more closely packed than BCC. Infact BCC has more slip systems than FCC. But they are not as closely packed as FCC. For plastic deformation, we need atleast 5 independent slip systems. Both FCC and BCC have those. But the previously mentioned factor makes FCC more ductile than BCC.
•The Kurdjumov-Sachs (KS) relationship is specified as {110}bcc/{111}fcc, <111>bcc//<101>fcc. •These two differ by only a 5.6° rotation in the interface plane.
They are two of the cubic structures for crystals with atoms linked by ionic or covalent bonds. They are also known as BCC and FCC. Table salt, NaCl, and Silicon, for example, assume a FCC structure. For illustrations, please go to the related link.
FCC : (h k l) must all be either odd or even BCC : sum h + k + l must be even. (Otherwise, an in between plane will cancel the reflection)
In FCC iron, carbon atoms can occupy octahedral sites, contributing to solid solubility. BC iron has fewer octahedral sites available for carbon, limiting solid solubility. Therefore, more carbon can be accommodated in FCC iron despite having a smaller void space.
Crystals are those substances which possess Atoms arranged in a reagular manner.They can be either BCC, FCC or SC.
One is a federal commission and the other is a diamond. Unless you're referring to crystal structure: "FCC" is the abbreviation for face-centered-cubic, "BCC" is body-centered-cubic. Diamond is just cubic, which may seem bad, but this crystal structure is nearly indestructible.
p = n x Mr / Vc x NAwhere n is the atoms/unit cell e.g. fcc packing n = 4 and for bcc packing n = 2Mr is the Atomic Mass in g/molVc is the volume/unit cell cm3 = a3 where a can be found by the radius of the atom and the packing used. e.g in bcc packing it is "a = 4r/1.732" . In Fcc packing it is "a= sin (4r)" or "a = cos (4r)"NA is avorgados constant, = 6.023 x1023
how much is the heat of transformation ptassium(bcc) to potassium (fcc)? i.e., delta H?
p = n x Mr / Vc x NAwhere n is the atoms/unit cell e.g. fcc packing n = 4 and for bcc packing n = 2Mr is the atomic mass in g/molVc is the volume/unit cell cm3 = a3 where a can be found by the radius of the atom and the packing used. e.g in bcc packing it is "a = 4r/1.732" . In Fcc packing it is "a= sin (4r)" or "a = cos (4r)"NA is avorgados constant, = 6.023 x1023
Iron has a body-centered cubic (BCC) crystal structure at temperatures below 912°C and a face-centered cubic (FCC) structure at temperatures above 912°C.