Yes, a rechargeable battery with the same voltage (V) and current rating (mA) can typically be replaced with a non-rechargeable battery of the same specifications. However, it's important to consider that rechargeable batteries often have different discharge characteristics and voltage profiles compared to non-rechargeable ones. This means that while they may fit and function, their performance and longevity in the device could vary. Always check the device specifications and manufacturer's recommendations before making a substitution.
To find the total charge the battery can release, use the formula ( Q = I \times t ), where ( I = 85 , \text{mA} = 0.085 , \text{A} ) and ( t = 12 , \text{h} = 43,200 , \text{s} ). Thus, ( Q = 0.085 , \text{A} \times 43,200 , \text{s} = 3,672 , \text{C} ). To calculate the energy, use ( E = Q \times V ), where ( V = 1.2 , \text{V} ). Therefore, ( E = 3,672 , \text{C} \times 1.2 , \text{V} = 4,406.4 , \text{J} ).
This will depend on the size of the 12 v battery.
No
Internal resistance is approximately equal to 94.667
V = IR, so if you double the voltage without changing the resistance, the current will also double.
You'll get a reading on the ammeter showing 15 mA
This video tutorial by fraviaseeker worked for me. http://www.youtube.com/watch?v=QXaIlyjvvSE It basically resets the batteries charge indicator circuit, which allows it to fully charge.
Find a volt meter, check the battery voltage with the engine stopped, it should be a around 12 V. Now start the engine and the voltage should be around 13.5 V. If the alternator isn't putting out about 13.5 (+/- .5 V) the replacment alternator could be bad or you might have a bad connection somewhere.
The 2.4 v battery doesn't have as many volts so the phone has less battery time, so you need to charge it more often, than the 3.6 v battery. Hope I helped you!
It depends on the voltage and current ratings of the battery. Most rechargeable batteries have these values printed on them. Lets say it is 1.25 V and it is 2000 mAh. This means it can provide, ideally, 1.25 and 2 amp for 1 hour (1.25 V and 1 amp for 2 hours). I think you got the idea. So it is 1.25*2=5 Watts.
In a boolean algebraic expression if the ^ is replaced by v and v replaced by ^ then that becomes dual of that boolean expression.
Depends on:-Technology.Lead AcidNiCadNiMhetccapacityHow many Amp hours.Chargerfast chargertrickle chargerIntelligent chargerVented or non-vented.