Yes, a rechargeable battery with the same voltage (V) and current rating (mA) can typically be replaced with a non-rechargeable battery of the same specifications. However, it's important to consider that rechargeable batteries often have different discharge characteristics and voltage profiles compared to non-rechargeable ones. This means that while they may fit and function, their performance and longevity in the device could vary. Always check the device specifications and manufacturer's recommendations before making a substitution.
To find the total charge the battery can release, use the formula ( Q = I \times t ), where ( I = 85 , \text{mA} = 0.085 , \text{A} ) and ( t = 12 , \text{h} = 43,200 , \text{s} ). Thus, ( Q = 0.085 , \text{A} \times 43,200 , \text{s} = 3,672 , \text{C} ). To calculate the energy, use ( E = Q \times V ), where ( V = 1.2 , \text{V} ). Therefore, ( E = 3,672 , \text{C} \times 1.2 , \text{V} = 4,406.4 , \text{J} ).
This will depend on the size of the 12 v battery.
No
Internal resistance is approximately equal to 94.667
V = IR, so if you double the voltage without changing the resistance, the current will also double.
You'll get a reading on the ammeter showing 15 mA
This video tutorial by fraviaseeker worked for me. http://www.youtube.com/watch?v=QXaIlyjvvSE It basically resets the batteries charge indicator circuit, which allows it to fully charge.
To convert milliamperes (mA) to watts (W), you need to know the voltage (V) in volts that the current is operating at. The formula is: Watts (W) = Volts (V) × Amperes (A). Since 1 mA is equal to 0.001 A, you can convert mA to A and then use the formula: W = V × (mA/1000).
Find a volt meter, check the battery voltage with the engine stopped, it should be a around 12 V. Now start the engine and the voltage should be around 13.5 V. If the alternator isn't putting out about 13.5 (+/- .5 V) the replacment alternator could be bad or you might have a bad connection somewhere.
It depends on the voltage and current ratings of the battery. Most rechargeable batteries have these values printed on them. Lets say it is 1.25 V and it is 2000 mAh. This means it can provide, ideally, 1.25 and 2 amp for 1 hour (1.25 V and 1 amp for 2 hours). I think you got the idea. So it is 1.25*2=5 Watts.
Depends on:-Technology.Lead AcidNiCadNiMhetccapacityHow many Amp hours.Chargerfast chargertrickle chargerIntelligent chargerVented or non-vented.
In a boolean algebraic expression if the ^ is replaced by v and v replaced by ^ then that becomes dual of that boolean expression.