To find the current that a 12-volt battery can drive through a 6-ohm light bulb, you can use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). Therefore, I = V/R = 12 volts / 6 ohms = 2 amps. Thus, the 12-volt battery can drive 2 amps of current through the 6-ohm light bulb.
When a battery is connected to a light bulb, the electrical current flows from the battery through the wire, causing the filament in the light bulb to heat up and emit light. The battery acts as a power source, providing the necessary voltage and current to illuminate the bulb.
In a battery-powered flashlight, chemical energy stored in the battery is converted into electrical energy when the battery generates a current. The electrical energy is then converted into light energy when the current passes through the light bulb or LED, producing light.
To light up, the bulb needs an electrical current flowing through it. This current is typically provided by connecting the bulb to a power source, such as a battery or outlet. Once the current flows through the bulb's filament, it heats up and produces light.
The battery light indicates that the battery is not receiving a charging current. You may have a bad alternator or a broken drive belt (if you have a broken belt you'll have overheating and power steering problems too, though).
When the flashlight is ON , electrical current is flowing from one terminal of thebattery, through the light-bulb filament, to the other terminal of the battery.
Electricity can flow in an electric circuit by a battery. The battery creates electrons, which flow through the wire, and then go into a light bulb. (That is how a light bulb in a circuit lights up.) A series circuit is a circuit with one wire that electrons can flow through. Also, there can be more than one light bulb connecting to the same wire. A parallel circuit is a circuit with light bulbs that have their own wire.ClarificationThe above answer, unfortunately, perpetuates the myth that current leaves a battery, and finds its way around a circuit. This is not the case at all. It is the load that 'draws' the current from the battery and it is the load that determines the size of that current.
Closed circuits work, they have all the wires connecting from the battery, the switch and the lightbulb that is needed for the electrical current to flow through the battery through the closed switch into the light bulb and back into the battery. Therefore it works.
Nothing will happen. It requires two wires to complete the circuit. Electrical current travels from the battery terminal through the wire to a metal portion of the base of the lightbulb. The current then travels up through the filament wire which glows as the current travels through. The current then travels back down the other side of the filament wire to the base of the bulb and thus through the second wire back to source, which is the battery.
Light bulb in the home - alternating current (A/C) Light bulb in a car - direct current (D/C) Output of a battery charger - direct current Input of a battery charger - usually alternating current
Yes, electrical energy can be used to drive chemical reactions in a battery to store energy in the form of chemical energy. Additionally, electrical energy can be converted into light energy by passing an electric current through a light bulb or LED.
A current is the flow of electric charge, which requires a potential difference (voltage) to drive it. In the case of a light bulb, the voltage from a source (such as a battery or outlet) is needed to create the electric field that allows the electrons to flow through the filament of the bulb, generating light and heat in the process. Without this applied voltage, there is no driving force to push the electrons through the circuit, so no current flows.
check the radiator. ;)