To calculate the grams of the solute ( \text{K}_2\text{Cr}_2\text{O}_7 ) in 15.0 mL of a 0.736 M solution, use the formula:
[ \text{grams} = \text{Molarity (M)} \times \text{Volume (L)} \times \text{Molar mass (g/mol)} ]
First, convert 15.0 mL to liters (0.015 L) and find the molar mass of ( \text{K}_2\text{Cr}_2\text{O}_7 ) (approximately 294.19 g/mol). Then calculate:
[ \text{grams} = 0.736 , \text{mol/L} \times 0.015 , \text{L} \times 294.19 , \text{g/mol} \approx 3.25 , \text{g} ]
Thus, there are approximately 3.25 grams of ( \text{K}_2\text{Cr}_2\text{O}_7 ) in 15.0 mL of the solution.
it has exactly 29.34098 grams of solute
To find the grams of solute, first calculate the moles of KBr in 365 mL of 0.590 M solution. This is done by multiplying the volume (in liters) by the molarity. Then, use the molar mass of KBr to convert moles to grams.
The solubility is expressed in grams of solute dissolved in 1 liter of solvent, at a given temperature.
The solubility is expressed in grams of solute dissolved in 1 liter of solvent, at a given temperature.
To determine the number of moles in a solution, you can use the formula: moles mass of solute (in grams) / molar mass of solute (in grams per mole). This calculation helps you find the amount of substance in the solution.
The answer is 26,3 g.
The answer is: Concentration can be expressed as grams of solute per milliliter of solvent.
the molar mass of the solute. The molar mass is the weight in grams of one mole of a substance and is typically found on the periodic table. Dividing the given grams of solute by the molar mass will give you the amount of solute in moles.
200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.
Isotonic saline typically has a concentration of 0.9% sodium chloride (NaCl). To find the grams of solute in 73.0 mL of isotonic saline, you can use the formula: grams of solute = volume (mL) × concentration (g/mL). Since 0.9% saline means 0.9 grams of NaCl per 100 mL, for 73.0 mL, the calculation is (73.0 mL × 0.009 g/mL) = 0.657 grams of NaCl.
Ethanol is the solvent and sucrose is the solute.
The amount of solute that will dissolve in water at a specific temperature depends on the solubility of the solute at that temperature. You need to check the solubility of the specific solute at the specified temperature (in degrees Celsius) to determine how many grams will dissolve in 100 grams of water.