To calculate the heat required to raise the temperature of aluminum, you can use the formula ( Q = mc\Delta T ), where ( Q ) is the heat energy, ( m ) is the mass (100 g), ( c ) is the specific heat capacity of aluminum (approximately 0.897 J/g°C), and ( \Delta T ) is the change in temperature (150°C - 30°C = 120°C). Plugging in the values:
[ Q = 100 , \text{g} \times 0.897 , \text{J/g°C} \times 120 , \text{°C} \approx 10764 , \text{J}. ]
Thus, you need about 10,764 Joules of heat.
It would take more energy to increase the temperature of water by 5 degrees than aluminum. This is because water has a higher specific heat capacity, meaning it requires more energy to raise its temperature compared to aluminum.
The specific heat capacity of aluminum is 0.9 J/g°C. To calculate the energy required to raise the temperature of 0.2kg of aluminum by 3 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. Substituting the values into the formula, Energy = 0.2kg x 0.9 J/g°C x 3°C = 0.54 Joules.
The heat energy required can be calculated using the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the aluminum (0.055 kg), c is the specific heat capacity of aluminum (900 J/kg°C), and ΔT is the change in temperature (94.6°C - 22.4°C = 72.2°C). Plugging in the values, we get Q = 0.055 kg * 900 J/kg°C * 72.2°C = 3582.7 J. Hence, 3582.7 Joules of heat energy is needed to raise the temperature of the aluminum sample.
Starting from the same temperature and for the same amount of heat input, aluminum would wind up with a higher temperature than water because water has a higher heat capacity (it takes more energy to raise its temperature) than aluminum.
Aluminum needs less energy than lead to raise its temperature by one degree, as aluminum has a lower specific heat capacity compared to lead. This means that aluminum can absorb and release heat more easily than lead for the same change in temperature.
The specific heat capacity of aluminum is 0.897 J/g°C. To convert this to kcal/g°C, we divide by 4.184 to get 0.214 kcal/g°C. Therefore, the total kilocalories of heat required to raise the temperature of 225g of aluminum from 20°C would be 225g * 20°C * 0.214 kcal/g°C = 966 kcal.
The specific heat capacity of aluminum is 0.897 J/g°C. By using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, you can calculate that 5,381.25 Joules of heat energy must be added to raise the temperature of the aluminum from 25°C to 135°C.
To raise the temperature of a substance, you need to calculate the heat energy using the specific heat capacity of the substance. Without knowing the specific heat capacity of the substance in question, it's not possible to determine the exact amount of energy required to raise the temperature from 30 to 45 degrees Celsius.
Yes, aluminum will heat up in the sun as it absorbs and retains heat well. Its thermal conductivity allows it to quickly raise in temperature when exposed to sunlight.
The specific heat capacity of aluminum is 900 J/kg°C. The change in temperature is 3°C. Using the formula Q = mcΔT, the energy required would be 0.2 kg * 900 J/kg°C * 3°C = 540 J. So, the energy required to raise the temperature is 540 Joules.
Aluminum requires the least amount of energy to raise its temperature compared to wood, water, and gold. This is because aluminum has a lower specific heat capacity, meaning it can heat up more quickly with less energy input.
The specific heat of the substance.