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How many calories is needed to heat 30g of water from 13C to 25C?
Using the formula Q=mcΔT, the amount of heat energy required is (30g)(4.18J g-1 K-1)(12K) = 1504.8J = 360 calories.
How many calories of heat are required to raise the temperature of 550g of water from 12.0 C to 18.0 C?
Q=6*550*1.00q=3300
How many calories of heat are required to raise the temperature of 15 g water (specific heat = 1.00 cal/g·°C) from 25 °C and 42 °Cshow work?
2pp
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many calories does it take to heat 1 liter of water 1 degree?
It takes 1000 calories to heat 1 litre of water 1 degree C.
How many calories are required to heat 37.4g of lead from 15 to 60 degrees Celsius?
This heat is 51, 33 cal.
How many calories would it take to heat up Lake Michigan by 1 degree Celsius?
To calculate the calories required to heat up Lake Michigan by 1 degree Celsius, you would need to know the specific heat capacity of water (4.186 J/g°C) and the mass of water in Lake Michigan. The formula to calculate the energy required is: Energy = mass of water x specific heat capacity of water x change in temperature. This would give you the calories needed to heat up Lake Michigan by 1 degree Celsius.
How many calories are required at 0 degree celsius to melt an ice cube with a mass of 25grams?
For water, the heat of fusion is 80 cal/g. So in other words, this is how many calories are needed to melt 1 gram of water that is frozen. Conversely, when you freeze 1 gram of water, you remove 80 calories of heat from it.... So, you multiply the calories needed to unfreeze a gram of water by the number of grams you have. In this case, 80 * 25 = 2000 Calories
How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?
The heat energy required to melt ice at 0 degrees Celsius is called the heat of fusion. For ice, the heat of fusion is approximately 334 J/g. To convert this to calories, divide by 4.184 J/cal, which gives you approximately 80 calories of heat energy needed to melt 10 grams of ice.
How many calories are required to melt a 1.52 g ice cube?
how many calories are required to melt a 1.52g ice cube?
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How many calories of heat is released when one gram of water vapor condenses into liquid water?
When one gram of water vapor condenses into liquid water, it releases about 2260 joules (540 calories) of heat energy. This process is called the latent heat of vaporization.
