How many calories would it take to raise the temperature of 200 grams of water from 5 degress celsius to 85 degrees celsius?

Answer 1

m=225 g

Delta T (change in temperature)= 33 C degrees

c (specific heat water liquid)= 1 cal/g(C)

Q=?

Q=mc(delta T)

Q=225g(1 cal/g(C degrees))(33 C degrees)

Q= 7425 calories

Answer 2

I need to find Joules first.

q = mass * specific heat * change in temperature

q = (200 grams)(4.180 J/gC)(85 C - 5 C)

= 66880 Joules

-----------------------now to convert

66880 Joules (1 calorie/4.184 Joules)

= 1.6 X 104 calories

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Answer 3

I will have to work in Joules, then convert.

q(Joules) = mass * specific heat * change in temperature

q = (450 grams)(4.180 J/gC)(85.5 C - 80.5 C)

= 9405 Joules

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9405 Joules (1 calorie/4.184 Joules)

= 225 calories

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Answer 4

1 calorie is the heat to raise 1 gram of water by 1 deg celsius. You have 200 grams being raised by 80 deg celsius, so the number of calories is 200 x 80 =16,000

Answer 5

200 calories, but we must remember the calories use to measure food are really kilocaloriesor 1000 times greater than a calorie which is the heat energy needed to raise 1 gram 1° Celsius

Answer 6

750 calories assuming no change of state (i.e. solid to liquid or liquid to gas) or 3138 joules