Denatured
When a protein loses its three-dimensional structure it's considered denatured.
The configuration of the lithium ion (Li⁺) is 1s². In its neutral state, lithium has the electron configuration of 1s² 2s¹, but when it loses one electron to become Li⁺, it loses the 2s electron, leaving only the 1s electrons.
Argon. Calcium has the electron configuration 1s2 2s2 2p6 3s2 3p6 4s2, and when it loses its valence electrons (the outermost 4s2 electrons) it has a configuration identical to argon. If you don't know about sublevels, then disregard that. Calcium has a configuration of 2-8-8-2, and when it loses its 2 valence electrons, it has a configuration identical to argon in the ground state. Hope that cleared it up
The denaturation temperature of the protein in question is the temperature at which the protein loses its structure and function.
The electron configuration of Cu+1 is [Ar] 3d10 4s1. When copper loses one electron to become a +1 ion, it loses the 4s electron first, followed by one of the 3d electrons to attain a stable electron configuration.
The noble gas configuration of Mg2+ is [Ne] because the magnesium atom loses two electrons to form the Mg2+ ion. The electron configuration of Ne is 1s2 2s2 2p6, so when Mg loses its two valence electrons, it achieves a stable electron configuration similar to that of the noble gas Ne.
The electron configuration of zirconium (Zr) is Kr 5s² 4d². When zirconium loses three electrons to form Zr³⁺, it typically loses the two 5s electrons first, followed by one 4d electron. Therefore, the electron configuration for Zr³⁺ is Kr 4d¹.
The electronic configuration of potassium, K, is [Ar]4s^1. When potassium loses one electron to become a K+ ion, the electronic configuration changes to that of argon [Ar].
When an atom becomes an ion, it gains or loses electrons to achieve a full outer electron shell, resulting in a change in electron configuration. For example, a neutral sodium atom (1s2 2s2 2p6 3s1) loses one electron to become a sodium ion (1s2 2s2 2p6). The electron configuration of the ion reflects this change in the number of electrons.
No.
Scandium typically loses electrons to form a +3 oxidation state. It loses electrons to achieve a stable electron configuration similar to the nearest noble gas, argon.
The electron configuration of boron is 1s2 2s2 2p1. When boron becomes an ion, it typically loses its outer electron to achieve a stable electron configuration. Therefore, the electron configuration of a boron ion is typically 1s2 2s2.